That's one term. You need at last two to find an LCM. That factors to t(t + 2)(t + 2)
2
9t = 4t + 120 9t-4t = 4t - 4t + 120 5t = 120 5t/5 = 120/5 t = 24 24 is your answer
If 4t + 5 = 37, then t = 8.
4t +7
T+(3-2t)=4t+1. Assuming the two T's , T and t are the same variable, lets proceed. t+(3-2t)=4t+1 3-t=4t+1 2-t=4t 2=5t last step is yours
That's one term. You need at last two to find an LCM. That factors to t(t + 2)(t + 2)
4t-1 = t+2 3t -1 = 2 3t = 3 t = 1
2
9t = 4t + 120 9t-4t = 4t - 4t + 120 5t = 120 5t/5 = 120/5 t = 24 24 is your answer
If 4t + 5 = 37, then t = 8.
4t +7
3s + 4t + 2s + 5s + 6tGroup all of the like 's' terms & 't' terms together:(3s+2s+5s) + (4t + 6t)10s + 10t or 10(s+t)
math
If you mean: 5y(4t-2) then it is 20ty-10y
7s + 4t
4t - 2p