x(4x-2)
4x - 5y = -2 so 5y = 4x + 2 or y = 4/5x + 2/5 Now that it is in the standard form, the slope is the coefficint of x ie 4/5.
5x x 4x = 20x^2 5x + x + 4x = 10x
x = 4.5
Well By what i can guess with your representation you want (x-2x)^2 =x^2+4x^2-4x^2=x^2
y=-x^2+4x-3
It is x^3 - x^2 - 4x + 4 = 0
x(4x-2)
4x - 5y = -2 so 5y = 4x + 2 or y = 4/5x + 2/5 Now that it is in the standard form, the slope is the coefficint of x ie 4/5.
5x x 4x = 20x^2 5x + x + 4x = 10x
If you mean y = -x+3 then it is x+y-3 = 0 in standard form
x = 4.5
Well By what i can guess with your representation you want (x-2x)^2 =x^2+4x^2-4x^2=x^2
Standard form is in the form of Ax+By=C . A must be positive, not a fraction. So, this one is 4x-y=-7 because the coefficient of x has to be changed.
3+4x=2y-9 Convert to standard form: 2y = 4x+12 or y = 2x+6 The slope, then, is the coefficient of x ie 2.
x² + y² - 4x + y - 1 = 0 ( x² - 4x ) + ( y² + y ) = 1 ( x² - 4x + 4 ) + [ y² + y + (1/4) ] = 1 + 4 + (1/4) ( x - 2 )² + [ y + (1/2) ]² = [ √(21) / 2 ]² This equation represents a Circle with Centre ≡ ( 2, -1/2 ) and Radius = √(21) / 2. ________________________________________ Happy To Help ! ________________________________________
Points: (2, 2) and (6, 3) Slope: 1/4 Equation: y = 1/4x+3/2 In standard form: x-4y+6 = 0