It is x^3 - x^2 - 4x + 4 = 0
x3 + 4x2 - 25x - 100 = 0
x3 - 2x2 - 25x + 50 = 0
The polynomial is (x + 1)*(x + 1)*(x - 1) = x3 + x2 - x - 1
the zeros of a function is/are the values of the variables in the function that makes/make the function zero. for example: In f(x) = x2 -7x + 10, the zeros of the function are 2 and 5 because these will make the function zero.
by synthetic division and quadratic equation
x3 + 4x2 - 25x - 100 = 0
x3 - 2x2 - 25x + 50 = 0
The zeros of a polynomial represent the points at which the graph crosses (or touches) the x-axis.
Polynomial fuction in standard form with the given zeros
If the cubic polynomial you are given does not have an obvious factorization, then you must use synthetic division. I'm sure wikipedia can tell you all about that.
The polynomial is (x + 1)*(x + 1)*(x - 1) = x3 + x2 - x - 1
the zeros of a function is/are the values of the variables in the function that makes/make the function zero. for example: In f(x) = x2 -7x + 10, the zeros of the function are 2 and 5 because these will make the function zero.
A cubic function is a polynomial function of degree 3. So the graph of a cube function may have a maximum of 3 roots. i.e., it may intersect the x-axis at a maximum of 3 points. Since complex roots always occur in pairs, a cubic function always has either 1 or 3 real zeros.
In the real domain, yes. In the complex domain, no.
by synthetic division and quadratic equation
Find All Possible Roots/Zeros Using the Rational Roots Test f(x)=x^4-81 ... If a polynomial function has integer coefficients, then every rational zero will ...
no a plynomial can not have more zeros than the highest (degree) number of the function at leas that is what i was taught. double check the math.