4(y + 2)(y + 2)
4y2 + 16y + 16 = 4(y2 + 4y + 4) = 4(y2 + 2y + 2y + 2) = 4[y(y + 2) + 2(y + 2)] = 4(y + 2)2
11y + 16 + 5y = 16y + 16 = 16(y + 1)
4y2 + 25y + 6
(2y-11)^2
4(y + 2)(y + 2)
4(y + 2)(y + 2)
4y2 + 16y + 16 = 4(y2 + 4y + 4) = 4(y2 + 2y + 2y + 2) = 4[y(y + 2) + 2(y + 2)] = 4(y + 2)2
11y + 16 + 5y = 16y + 16 = 16(y + 1)
If 4*y*2+16*y+16: 8y+16y+16 24y+16 8(3y+2) -------------------------------------------- If 4*y**2+16*y+16: 4(y**2+4y+4) in ay**2+by+c: a=1 b=4 c=4 the multiples of b are: 1*4 2*2 the multiples of b that adds up to c is 2*2 4(y+2)(y+2) 4(y+2)**2
4y2 + 25y + 6
x^2 plus 16y?
(4y2 + 3)(4y2 - 6y + 3)(4y2 + 6y + 3)
Replace the y with a 3. 16 x 3 + 9 = 57
(2y-11)^2
(4y + 1)(y + 6)
(y - 5)(4y - 5)