Best Answer

4y2+16y+16=0

Divide by 4 on both sides: y2+4y+4=0

Factorise: (y+2)(y+2)=0

Therefore y= -2

Q: What is 4y2 plus 16y plus 16?

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4(y + 2)(y + 2)

4y2 + 16y + 16 = 4(y2 + 4y + 4) = 4(y2 + 2y + 2y + 2) = 4[y(y + 2) + 2(y + 2)] = 4(y + 2)2

11y + 16 + 5y = 16y + 16 = 16(y + 1)

4y2 + 25y + 6

(2y-11)^2

Related questions

4(y + 2)(y + 2)

4(y + 2)(y + 2)

4y2 + 16y + 16 = 4(y2 + 4y + 4) = 4(y2 + 2y + 2y + 2) = 4[y(y + 2) + 2(y + 2)] = 4(y + 2)2

11y + 16 + 5y = 16y + 16 = 16(y + 1)

If 4*y*2+16*y+16: 8y+16y+16 24y+16 8(3y+2) -------------------------------------------- If 4*y**2+16*y+16: 4(y**2+4y+4) in ay**2+by+c: a=1 b=4 c=4 the multiples of b are: 1*4 2*2 the multiples of b that adds up to c is 2*2 4(y+2)(y+2) 4(y+2)**2

4y2 + 25y + 6

x^2 plus 16y?

(4y2 + 3)(4y2 - 6y + 3)(4y2 + 6y + 3)

Replace the y with a 3. 16 x 3 + 9 = 57

(2y-11)^2

(4y + 1)(y + 6)

(y - 5)(4y - 5)