4y2+16y+16=0
Divide by 4 on both sides: y2+4y+4=0
Factorise: (y+2)(y+2)=0
Therefore y= -2
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4(y + 2)(y + 2)
4y2 + 16y + 16 = 4(y2 + 4y + 4) = 4(y2 + 2y + 2y + 2) = 4[y(y + 2) + 2(y + 2)] = 4(y + 2)2
11y + 16 + 5y = 16y + 16 = 16(y + 1)
4y2 + 25y + 6
(2y-11)^2