4(y + 2)(y + 2)
4y2+16y+16=0 Divide by 4 on both sides: y2+4y+4=0 Factorise: (y+2)(y+2)=0 Therefore y= -2
4y2 + 16y + 16 = 4(y2 + 4y + 4) = 4(y2 + 2y + 2y + 2) = 4[y(y + 2) + 2(y + 2)] = 4(y + 2)2
(4y + 1)(y + 6)
(2y + 3)(4y2 - 6y +9)
4y2 + 25y + 6
(4y2 + 3)(4y2 - 6y + 3)(4y2 + 6y + 3)
(2y + 3)(4y^2 - 6y + 9)
(3 - 2y)(3 + 2y)
If you're looking to factor this expression, then you need to find two values that add up -20, and which multiply to make 4. Unfortunately, no such terms exist, so this expression can not be factored.
(2y-11)^2
(y - 5)(4y - 5)