4y+4 = 2y+12 4y-2y = 12-4 2y = 8 y = 4
6m + m + m + 4y + n + y + 12 + 2n Group like terms: 6m + m + m + 2n + n + 4y + y + 12 Add: 8m + 3n + 5y + 12
4y + 19 = 74y = 7-194y = -124y/4 = -12/4y = -3
4y + 3 >= -94y >= -9 + -34y >= -12y >= -12/4y >= -3
That depends what the value of y is.
4y+4 = 2y+12 4y-2y = 12-4 2y = 8 y = 4
4y + 10 = 22 4y - 10 - 10 4y=12 4y 4y 4y=3
6m + m + m + 4y + n + y + 12 + 2n Group like terms: 6m + m + m + 2n + n + 4y + y + 12 Add: 8m + 3n + 5y + 12
There are infinite solutions, since you have 2 unknowns and 1 equation. x+4y=12 4y=12-x y=3-0.25x or x=12-4y If you choose an y or an x, the other is defined.
5y + 6
4y + 7 = 19 ∴ 4y = 12 ∴ y = 3
4y + 19 = 74y = 7-194y = -124y/4 = -12/4y = -3
42+4y -12 = 13y -12 -2y 4y -13y+2y = 12 -12 -42 -7y = -42 y = 6
4y + 3 >= -94y >= -9 + -34y >= -12y >= -12/4y >= -3
That depends what the value of y is.
x = 4 and y = 0
Factor out the 4. The answer is y-3/y+3