I count 53 times.
120
Because 53/200 times 100/1 = 26.5%
1/4 times 120120/460/230
(3/½) × 120 = (3 ÷ ½) × 120 = (3 × 2/1) × 120 = 3 × 2 × 120 = 720 3/(½ × 120) = 3 ÷ (120/2) = 3 × 2/120 = 6/120 = 1/20 = 0.05
I count 53 times.
4 1/2 x 53 1/3 = 240
120
there are 53 ones from 1-120
Because 53/200 times 100/1 = 26.5%
A regulation football field is 120yds long and 53 1/2 yd wide. What is the area of the field?
To determine the number of times the digit 1 appears between 1 and 120, we can consider each place value separately. In the units place, the digit 1 appears 12 times (1, 11, 21, ..., 111). In the tens place, the digit 1 appears 11 times (10, 11, 12, ..., 19). Therefore, the total number of times the digit 1 appears between 1 and 120 is 12 (from the units place) + 11 (from the tens place) = 23 times.
1/4 times 120120/460/230
6/120 written as a percentage is 6/120 times 100/1 = 5%
53 x 1
(3/½) × 120 = (3 ÷ ½) × 120 = (3 × 2/1) × 120 = 3 × 2 × 120 = 720 3/(½ × 120) = 3 ÷ (120/2) = 3 × 2/120 = 6/120 = 1/20 = 0.05
20 with 1/6 left over