5 x 17 = 85
5*5*17 = 425
If x ≡ 39 mod 357 then: x = 357k + 39 for some integer k. Now 357 = 21×17, and 39 = 2×17+5 → x = 21×17×k + 2×17 + 5 → x = 17(21k + 2) + 5 → x = 17m + 5 where m = 21k + 2 (is an integer) → x ≡ 5 mod 17 → the remainder when the number is divided by 17 is 5.
2125 = 5 x 5 x 5 x 17
1 x 85, 5 x 17, 17 x 5, 85 x 1.
x-17 = 16-5 x = 16-5+17 x = 28
2 x 5 x 5 x 17 = 850
5 x 17 = 85
5*5*17 = 425
By dividing by 5 and 17. 5 x 17 x 17 = 1445
X - 5 = 17 Add 5 to both sides of the equation: X = 22
2, 5 and 17
1 x 85, 5 x 17, 17 x 5, 85 x 1
1 x 85, 5 x 17, 17 x 5, 85 x 1.
As a product of its prime factors: 5 times 17 equals 85
If x ≡ 39 mod 357 then: x = 357k + 39 for some integer k. Now 357 = 21×17, and 39 = 2×17+5 → x = 21×17×k + 2×17 + 5 → x = 17(21k + 2) + 5 → x = 17m + 5 where m = 21k + 2 (is an integer) → x ≡ 5 mod 17 → the remainder when the number is divided by 17 is 5.
For 510: 2, 3, 5 and 17 For 544: 2 and 17