25a2-6400
The above is a perfectly correct answer to the question as posed.
However, the question as written makes so little sense that I suspect this is another homework assignment that got slightly garbled in transmission. The original question was very likely : -
5a2 - 80 = 0. Solve for a.
If so, the answer is a = +4 or -4.
2
It simplifies to 5a+4 !
Negative sixty-four minus four squared is equal to -80.
No
4a2 - 9a + 5 = 4a2 - 4a -5a + 5 = 4a(a - 1) - 5(a - 1) = (4a - 5)(a - 1)
2
It simplifies to 5a+4 !
The square root of 25a squared is 5a. The square root of 16 is 4.So the answer is (5a+4)(5a-4)
This is not a difficult factorisation, as it is merely a normal factorisation with "a" stuck on the end of each number. 25a(2) - 20ab + 4b(2) (2b-5a)(2b-5a) This is: 2bx2b=4b(2) 2bx-5a=-10ab (twice) -5ax-5a=25a
Negative sixty-four minus four squared is equal to -80.
It is: 5(x^2 -16)
Well, honey, 5a squared is just 5 times a squared. It's as simple as that. So if you're looking for the value of 5a squared, just make sure you don't forget to square that 'a' and multiply it by 5. Easy peasy lemon squeezy!
Solve this problem -x squared -40x- 80 =0
No
2a
5a2-15 = 5 (a2-3) = 5 (a-sqrt(3))(a+sqrt(3)) as a2-b2=(a-b)(a+b)
4a2 - 9a + 5 = 4a2 - 4a -5a + 5 = 4a(a - 1) - 5(a - 1) = (4a - 5)(a - 1)