25a2-6400
The above is a perfectly correct answer to the question as posed.
However, the question as written makes so little sense that I suspect this is another homework assignment that got slightly garbled in transmission. The original question was very likely : -
5a2 - 80 = 0. Solve for a.
If so, the answer is a = +4 or -4.
2
It simplifies to 5a+4 !
Negative sixty-four minus four squared is equal to -80.
No
4a2 - 9a + 5 = 4a2 - 4a -5a + 5 = 4a(a - 1) - 5(a - 1) = (4a - 5)(a - 1)
2
It simplifies to 5a+4 !
The square root of 25a squared is 5a. The square root of 16 is 4.So the answer is (5a+4)(5a-4)
This is not a difficult factorisation, as it is merely a normal factorisation with "a" stuck on the end of each number. 25a(2) - 20ab + 4b(2) (2b-5a)(2b-5a) This is: 2bx2b=4b(2) 2bx-5a=-10ab (twice) -5ax-5a=25a
Negative sixty-four minus four squared is equal to -80.
5a or 4a squared
It is: 5(x^2 -16)
In mathematics, the term "5a squared" can be written as "5a^2". This expression represents the product of 5 and the square of the variable "a". To calculate the value of 5a^2, you would square the value of "a" and then multiply the result by 5.
Solve this problem -x squared -40x- 80 =0
No
2a
5a2-15 = 5 (a2-3) = 5 (a-sqrt(3))(a+sqrt(3)) as a2-b2=(a-b)(a+b)