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this question makes no sense. do you mean what are the zeros/roots of this polynomial?
Factoring trinomials are fun!
5x2 - 8x - 4
(5x + 2)(x - 2)
Never forget to check:
5x2 - 10x + 2x - 4
5x2 - 8x - 4
Good everything is in order, now set each parentheses equal to zero to solve for x
5x + 2 = 0
5x = -2
x = - 2/5
x - 2 = 0
x = 2
All done! Now we know the solution set is {-2/5, 2}. Remember smallest number always goes first.
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Find the factors of x3-5x2 8x-4 how to solve this equation?
5x2-8x-4
What is the answer to 24x3-5x2-48x-8 divided by 8x plus 4?
If you notice, 8x + 4 = 4(2x + 1), but there is an odd coefficient for x2, so there is guaranteed to be some remainder (that is 8x + 4 is not a factor of the polynomial): (24x3 - 5x2 - 48x - 8) ÷ (8x + 4) = 3x2 - 2x - 5 - (x2 - 12)/(8x + 4)
How do you do (5x2 8x)-(3x2-x)?
In algebra and mathematics the simple above equation can be written and simplified as follows . (5x2 8x)-(3x2-x) = 10 + 8x -6 +x = 4 +7x.
How do you factor x3 - 5x2 8x -4?
(x - 2)(x - 2)(x - 1)
What are the solutions of 5x2 plus 8x equals 7?
5x2 + 8x = 7 5x2 + 8x - 7 = 0 This cannot be factorised so the solutions need to be determined using the quadratic formula The solutions are {-8 ± sqrt[82 - 4*5*(-7)]}/(2*5) = {-8 ± sqrt[64 + 140]}/10 = {-8 ± sqrt[204]}/10 = -2.22829 and 0.62829 (to 5 dp)
