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What is the general form of the perpendicular bisector equation of the line segment of z 2z and 3z 8z?
Mid-point: (3z+z)/2, (2z+8z)/2 = (2z, 5z) Slope: (8z-2z)/(3z-z) = 6z/2z = 3 Perpendicular slope: -1/3 Equation: y -5z = -1/3(x -2z) => y = -1/3x+2z/3+5z => y = -1/3x+17z/3 General form of the bisector equation: x+3y-17z = 0
What does 3z plus 8 plus 2z plus 6 equal?
3z + 8 + 2z + 6 = 5z + 14
How do you factor 5a2z-4a2c 15xz-12xc?
(5a)(2z) - (4a)(2c) + 15xz - 12xc group and factor each group = 2a(5z - 4c) + 3x(5z - 4c) factor again (5z - 4c)(2a + 3x)
2z plus 9.75-7z equals 5.15?
2z + 9.75 - 7z = 5.15grouping terms, -5z = 5.15 - 9.75subtracting terms on right side, -5z = -4.6dividing both sides by -5, z = 0.92Verifying:Left Side = (2 x .92) + 9.75 - (7 x .92) = 1.84 + 9.75 - 6.44 = 11.69 - 6.44 = 5.15 = Right Side
What is the answer for adding polynomials 2z plus 3z plus 5z plus 4 plus 6x-2x?
We can simplify this expression by combining the like terms. Here the likes terms are the z's and the x's.2z + 3z + 5z = 10z. (If we have 2 of something and add three of the same thing and then 5 of the same thing we will end up with 10 of that thing).Likewise we can combine the x's.6x - 2x = 4x. (You could think of this as 6x + - 2x if this helps with the idea of "combining".)Therefore we are able to simplify this expression as:2z + 3z + 5z + 4 + 6x - 2x = 10z + 4 + 4x.
