√18xy = √(9*2xy) = √9*√2xy = 3*√(2xy)
2xy + 6 = 4xyz Divide through by 2: xy + 3 = 2xyz 3 = 2xyz - xy = y*(2xz - x) Therefore, y = 3/(2xz - x) provided that 2xz - x is not zero.
4xy - 2xy
Neither of those expressions is a binomial. [ 2y + 2xy ] is a binomial.
0.3333
2xy
(2xy)x=2x2y
Since 2xy is a factor of 2x2y, it is automatically the GCF.
2xy + 6xy = 8xy
(x + 4y)(x - 6y)
√18xy = √(9*2xy) = √9*√2xy = 3*√(2xy)
2xy + 6 = 4xyz Divide through by 2: xy + 3 = 2xyz 3 = 2xyz - xy = y*(2xz - x) Therefore, y = 3/(2xz - x) provided that 2xz - x is not zero.
The three terms are: -3xy2, 2xy and -4y3
4xy - 2xy
3xy^(3)2xy(6) = 6x^(2)y^(9).
3xy and 2xy. You can see that 3xy and 2xy have something in common with each other. They both have xy and the end of them. Hope this helped.
(2xy-4x)+ (8y-16)=2xy-4x+8y-16, which factors as 2(x+4)(y-2)