Q: What is 64 didved by 2?

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It is: 54/9 = 6

It is: 2*2*2*2*2*2 = 64 or as 26 = 64

is 2 divisor of 64

As a product of its prime factors: 2*2*2*2*2*2 = 64 or as 26 = 64

2/64 cancel down by '2' Hence 1/32 The answer!!!!!

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3/2 ÷ 3/5 = 3/2 x 5/3 = 5/2 = 21/2

It is: 54/9 = 6

The prime factorization of 64 is 2x2x2x2x2x2 or 2^6. 2 x 2 x 2 x 2 x 2 x 2 = 64

64 = 2 * 2 * 2 * 2 * 2 * 2 = 26

64 I 32, 2 I I 16, 2 2 I I I 8, 2 2 2 I I I I 4, 2 2 2 2 I I I I I 2,2 2 2 2 2 your primes for 64 are 2,2,2,2,2,2. 2x2x2x2x2x2=64 or 26 is 64.

Composite 2*2*2*2*2*2 = 64 26 = 64

You find numbers that divide evenly into 64, such as for example, 1, 2, 4, 8, 16, 32, and 64. Then sharpen your pencil and start writing. 1 x 64 = 64 2 x 32 = 64 4 x 16 = 64 8 x 8 = 64 2 x 2 x 16 = 64 2 x 4 x 8 = 64 4 x 4 x 4 = 64 2 x 2 x 2 x 8 = 64 2 x 2 x 4 x 4 = 64 2 x 2 x 2 x 2 x 4 = 64 2 x 2 x 2 x 2 x 2 x 2 = 64

26 = 64 2*2*2*2*2*2 = 64 or 6.4*101

It is: 2*2*2*2*2*2 = 64 or as 26 = 64

(28 + 64)/2 = 92/2 = 46(28 + 64)/2 = 92/2 = 46(28 + 64)/2 = 92/2 = 46(28 + 64)/2 = 92/2 = 46

2 x 2 x 2 x 2 x 2 x 2 = 64 or 26 = 64

64^(2/3) = ((64^(1/3)^(2)) 64^(1/3) is the 'cube root of '64' , which is '4' Hence (4^(2)) = 16 Hence 64^(2/3) = 16