To multiply the expressions (6n) and (2n), you multiply the coefficients (6 and 2) and the variable terms. This results in (6 \times 2 = 12) and (n \times n = n^2). Therefore, (6n \times 2n = 12n^2).
Chat with our AI personalities
5n+6n-2n can be solved by combining like terms. Combine 5n and 6n and -2n to get 9n.
-6n-2n 16 can be solved mathematically getting n = - 2.
Move the 2n over the equals sign. Become 4n (as 6n-2n= 4n) and then if 4n=16 then n=4.
The answer is: n=4.
Let 2n be the first integer, then the next on is 2n+2 and the one after is 2n+4 so adding all three we have 6n+6=108 or 6n=102 and we want 2n so divide we divide 6n by 3 and we have 2n=34, and 2n+2=36 and lastly 2n+4=38 so 34, 36, 38 are the even integers we seek.