0
Want this question answered?
Be notified when an answer is posted
Add your answer:
Earn +20 pts
How do you solve -6n-2n?
5n+6n-2n can be solved by combining like terms. Combine 5n and 6n and -2n to get 9n.
How do you solve this -6n-2n 16?
-6n-2n 16 can be solved mathematically getting n = - 2.
6n equals 2n plus 16?
Move the 2n over the equals sign. Become 4n (as 6n-2n= 4n) and then if 4n=16 then n=4.
What is the answer to 6n 2n 16?
The answer is: n=4.
What are three consecutive even integers whose sum is 108?
Let 2n be the first integer, then the next on is 2n+2 and the one after is 2n+4 so adding all three we have 6n+6=108 or 6n=102 and we want 2n so divide we divide 6n by 3 and we have 2n=34, and 2n+2=36 and lastly 2n+4=38 so 34, 36, 38 are the even integers we seek.
5n 6n - 2n?
5n + 6n - 2n
How do you solve -6n-2n?
5n+6n-2n can be solved by combining like terms. Combine 5n and 6n and -2n to get 9n.
How do you solve 5n 6n-2n?
5n+6n-2n can be solved by combining like terms. Combine 5n and 6n and -2n to get 9n.
What is -6n-2n equals 16 equal to?
If: -6n-2n = 16 Then: n = -2
What is 5 over 2n plus 3 over 3n?
15/6n + 6/6n = 21/6n = 7/2n
What is 6n-3 equals 2n plus 9?
6n -3=2n+9 6n-2n=9+3 4n=12 n=12/4 n=3
How do you solve this -6n-2n 16?
-6n-2n 16 can be solved mathematically getting n = - 2.
6n equals 2n plus 16?
Move the 2n over the equals sign. Become 4n (as 6n-2n= 4n) and then if 4n=16 then n=4.
What is the answer to 6n 2n 16?
The answer is: n=4.
Which is the complete factorization of 2n-6n-36?
First we must collect and simplify 'like terms' 2n-6n-36. 2n-6n = -4n Therefore, -4n-36 Take out the greatest common factor. -4 (n+9) Ans = -4 (n+9)
What are three consecutive even integers whose sum is 108?
Let 2n be the first integer, then the next on is 2n+2 and the one after is 2n+4 so adding all three we have 6n+6=108 or 6n=102 and we want 2n so divide we divide 6n by 3 and we have 2n=34, and 2n+2=36 and lastly 2n+4=38 so 34, 36, 38 are the even integers we seek.
What is 2n times 3n?
The expression 2n times 3n can be simplified by multiplying the coefficients (2 and 3) to get 6, and multiplying the variables (n and n) to get n^2. Therefore, 2n times 3n simplifies to 6n^2. This represents the product of 2n and 3n in algebraic terms.
