(2x + 1)(2x + 1) or (2x + 1)2 so x = -0.5
Numerator = (x + 4)*(x + 3) Denominator = (2x - 1)*(x + 3) Calcelling out the common factor, (x + 3), the answer is (x + 4) divided by (2x - 1) provided x ≠ 0.5
The answer is (2x^2+3)(4x+1)
2(x - 1)(2x + y)
(2x - 9)(2x - 9) or (2x - 9)2
It is: 4x squared
-x2+2x
7x2 -4x -5x2 +2x = 2x2 -2x
(2x-1)(2x-1) = 4x^2 -4x + 1
y = 2x^(2) + 4x + 8 dy.dx = 2(2)x^(2-1) + 4x^(1-1) +8x^(0) dy/dc = 2(2)x^(1) + (1)4x^(0) + (0)8x^(0-1) dy/dx = 4x + 4 + 0 dy/dx = 4x + 4 *The derivative). NB #1 The original index number becomes a coefficient ( in brackets). Then subtract '1' from the original index value, for the new index value. #2 Any term raised to the power of '0' = 1. #3 Any term multiplied by '0' = 0.
4
(2x+3)(2x+4)
It equals 53X- a number is squared when it is multiplied by itself, so 7X by 7X = 49X. 2X by 2X =4X, so 49X + 4X is 53X.
(2x + 1)(2x + 1) or (2x + 1)2 so x = -0.5
(2x - 3)(2x - 3)
Numerator = (x + 4)*(x + 3) Denominator = (2x - 1)*(x + 3) Calcelling out the common factor, (x + 3), the answer is (x + 4) divided by (2x - 1) provided x ≠ 0.5
The answer is (2x^2+3)(4x+1)