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The derivative of 2x2 + 4x + 8 is 4x+4.

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Q: What is the derivative of 2x-squared plus 4x plus 8?

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I am interpreting this as: Find the derivative of: y=((2x+5)8+4x)3 To find the derivative (y'), the chain rule must be applied. The "outermost" function of this compound function is t3 (t being an arbitrary quantity). The derivative of t3 is 3t2 * dt, where "dt" is the derivative of the quantity "t". Applying this, we arrive at a working definition of y': y' = 3((2x+5)8+4x)2(derivative of (2x+5)8+4x) The derivative of (2x+5)8+4x is found using basic derivative definitions and the chain rule again: 8(2x+5)7(2)+4 = 16(2x+5)7+4 So now we can write y' again: y'= 3((2x+5)8+4x)2(16(2x+5)7+4) = 48((2x+5)8+4x)2((2x+5)7+4) This can be further simplified, but this is an arduous process. If you need further simplification, feel free to contact me via private message.

4x + 8 + 7x + 12 = 11x + 20

4x+8

If: 4x+(-12) = 8 then 4x = 20 and x = 5

8 + y = 4x8 + y - 4x = 4x - 4x 8 + y - 4x = 0 8 - 4x + y = 0

-4x + 8 = -4 -4x + 8 - 8 = -4 -8 -4x = -12 -4x/-4 = -12/-4 x = 3

4x+32=-4x+16x4x+32=12x-4x -4x32=8x/8 /84=x

5x + 3 - 4 + 4x = 9x -1

3x-8

If the equation is y = 4x + 8, then the standard form is 4x - y + 8 = 0

8 + 4x - x = 8 3x = 8 - 8 x = 0

9x + 8 = 4x + 23Subtract 8 from both sides9x = 4x + 15Subtract 4x from both sides5x = 15Divide both sides by 5x = 3

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