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78 + 79 + 80 + 80 + 81 + 81 = 479

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13y ago

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What is the mean of 78 79 80 80 81 81 81?

Assuming you mean the arithmetic mean, it is 80.


What is the variance in this problem 73 72 67 74 78 84 79 71 76 76 79 81 75 80 78 76 78?

The variance of 73 72 67 74 78 84 79 71 76 76 79 81 75 80 78 76 78 = 16.8456


What is the median 84 83 78 75 90 77 75 81 85 82 78 83 72 80 81 79 75 76 83 81 78 78?

83


77 plus 77 plus 78 plus 78 plus 78 plus 80 plus 81 plus 81 plus 81?

The answer is 711. Simply add up all of the numbers arithmetically like you would for two plus two. To make sure the answer is correct, check your work using a calculator.


What is 79 plus 2?

81


What is 85 plus 78 plus 80 plus 87 plus 93 plus 90 plus 84 plus 87 plus 81?

765


What is the mean of 81 76 94 81 79 and 78?

the mean is 79.75


What is 81 plus (a-3)?

78


What is 80 plus 1?

80+1 = 81


What sums equal 80?

There are infinitely many. Involving integers (whole numbers) there are: 0 + 80, 1 + 79, 2 + 78, .... 78 + 2, 79 + 1, 80 + 0, 81 + -1, 82 + -2, ..... When you include non-integers there are: ½ + 79½, 1½ + 78½, ... 1.1 + 78.9, 1.2 + 78.8, .... 3.1 + 76.9, 3.14 + 76.86, 3.141 + 76.859, 3.1415 + 76.8585, 3.14159 + 76.85841, ...., π + (80 - π)


What is 77 plus 81 plus 79 equal?

237


What set of numbers has a mean of 80?

There are an infinite number of sets with mean 80. Here are some: {80, 80, 80}, {80, 80, 80, 80, 80, 80} {79, 80, 81}, {79, 79, 80, 81, 81}, {79, 79, 80, 82} (1, 80, 159}, {-40, 200} To produce a set of n numbers with mean 80, start with any set of n-1 numbers. Suppose their sum is S. Then add the number 80*n-S to the set. You will now have n numbers whose sum is S+80*n-S = 80*n So the mean of this set is 80.