80+1 = 81
1/5 of 80 plus 1/2 of 60 is 46. 1/5 of 80 is 16 1/2 of 60 is 30
3y+2y+4+1=80 5y+5=80 5y=80-5 5y=75 y=15
If you mean: 80 = 3y+2y+4+1 then 80 =5y+5 and so y = 15
80
75
70 + 80 + 70 + 30+ 80 + 80+ 80 = 490
Presumably you want to know the value of y. 3y+2y+4+1 = 80 5y+5 = 80 5y = 80-5 5y = 75 y = 15
1
80 = 3y + 2y + 4 + 1 80 = 5y + 5 80 - 5 = 5y + 5 - 5 75 = 5y 75 / 5 = 5y / 5 15 = y
The answer to the equation 80 times 3 Y plus 2 Y plus 4 plus 1 equals -15. This is considered to be a math problem.
// Create a bunch of static arrays char name[80]; char names[80][80]; int nums[5]; float useless[1][1][1][1][1];
The answer is 560. Simply add the numbers together like you would for two plus two. To check your work, a calculator is the best option.