12 x 5 = 60
The sum of 3/5 and 7/5 is 10/5, which simplifies to 2.
They are 7 and 5.
16
2 + 5 = 7
(21/7) + (3 x 5) = 3 + 15 = 18
That number would be 3
To find 5 times the sum of 7 and 23, you first need to calculate the sum of 7 and 23, which is 30. Then, you multiply this sum by 5 to get the final answer. Therefore, 5 times the sum of 7 and 23 is 5 x 30, which equals 150.
that answer is 48.
3(y+7)
3*(t + 7) or 3t + 21
12 x 5 = 60
Any integer of which both 5 and 7 are factors.
You can find the sum of 8, 5, and 7, and then multiple that sum by 3, which is equal to 60.
The sum of 3/5 and 7/5 is 10/5, which simplifies to 2.
7 + 3b ≥ 12 Subtract 7 from both sides: 3b ≥ 5 Divide both sides by 3: b ≥ 5/3 or 1.66...
2 * 3 * 3 * 5 * 7 = 630