Three times the difference of a and m divided by twice their sum is equal to 6(a squared - m squared). 3(a - m)/2(a + m)
18 + 3 = 21
That means the number itself is divisible by three. the sum of the digits in 144, for example, is 9. 144 divided by 3 is 48. The sum of the digits in 21 is 3. 21 divided by 3 is 7.If the number is an even number and the sum of the digits is divisible by 3, the number is also divisible by 6. 144 is even and the sum of the digits is divisible by 3, so 144 is also divisible by 6. 144/6 = 24. And finally, if the sum is divisible by 9, the number itself is also divisible by 9. 27 is an example of this.
3
the sum of 3 times m and n
0.75
The number 3 can go in to 63 21 times. 63 divided by 3 equals 21.
3*(t + 7) or 3t + 21
Well 63 divided by 3 equals 21. So 3 times 21 equals 63. 21 is that number.
Three times the difference of a and m divided by twice their sum is equal to 6(a squared - m squared). 3(a - m)/2(a + m)
24
1.1547005383792515290182975610039
3/7 x 7/8 = 21/56 or 3/8
18 + 3 = 21
3 and 7 are the prime numbers because they cannot be divided by any number other than themselves and 1because 3+7 = 10 (Sum)and 3x7 = 21 (Product)
That means the number itself is divisible by three. the sum of the digits in 144, for example, is 9. 144 divided by 3 is 48. The sum of the digits in 21 is 3. 21 divided by 3 is 7.If the number is an even number and the sum of the digits is divisible by 3, the number is also divisible by 6. 144 is even and the sum of the digits is divisible by 3, so 144 is also divisible by 6. 144/6 = 24. And finally, if the sum is divisible by 9, the number itself is also divisible by 9. 27 is an example of this.
No, the sum of the digits is 9+5+7=21 so we know three is a factor because 21 is a multiple of 3.In face 957 divided by 3 is 319