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Which two numbers are seven and five units away from zero on a number line?
The two numbers that are seven and five units away from zero on a number line are 7 and -7 for the seven units, and 5 and -5 for the five units. Therefore, the complete set of numbers is -7, -5, 5, and 7.
What numbers are distance of 7 units from 1 on a number line?
To find the numbers that are 7 units away from 1 on a number line, you can add and subtract 7 from 1. This gives you two values: (1 + 7 = 8) and (1 - 7 = -6). Therefore, the numbers that are 7 units from 1 are -6 and 8.
What is the distance between 11 and 7 on a number line?
3 units
What is the distance between -7-3 on a number line?
-4
How many units is it from negative 5 to positive 2 on the number line?
7
How many units is it from 3 to -4 on a number line?
7
What two numbers are 7 units from 0 on a number line?
+7 and -7.
What is the distance between - 7 and 19 on a number line?
26 units
What is the distance between 11 and 7 on a number line?
3 units
What number is 7 units to the right of -4?
11
What is the distance between -7-3 on a number line?
-4
How many units is it from negative 5 to positive 2 on the number line?
7
What numbers are 5 units or more away from -2 on a number line?
7
What are two integers are 7 units away from the number 5 on a number line?
They are -2 and 12.
What whole numbers is six unit segment to the right of -4 on the number line above?
Well, when you start at -4 on the number line and move 6 units to the right, you'll end up at a new location. To find this new spot, you can simply add 6 to -4. So, -4 + 6 equals 2. That means the whole number that is six units to the right of -4 is 2.
What is the distance between -4 and 7 on a number line?
11 units away from each other
How do you represent Root 7 on number line?
Here is the answer to your question.Draw a number line (l) and mark the points O, A and B such that OA = AB = 1. Draw BC⊥ l such that BC = 1 units. Join OCIn right ∆OBC,
