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x2+7x-44 = (x-4)(x+11) when factored
x2-7x-44 = (x+4)(x-11) when factored
I don't know if you typed your question wrong... but I see it as 33-4x = 7x-44 33+44=7x+4x 77=11x 77/11=x x=7
7x = 3x - 12 4x=-12 x=-3
4x + 8 + 7x + 12 = 11x + 20
x2+7x-44 = (x-4)(x+11) when factored
x2-7x-44 = (x+4)(x-11) when factored
19
I don't know if you typed your question wrong... but I see it as 33-4x = 7x-44 33+44=7x+4x 77=11x 77/11=x x=7
44
If 7x - 5 = 44 Then 7x = 44 + 5 = 49 x = 49/7 Therefore, x = 7
x2+7x+12
X squared + 7X + 12?
28=8x+12-7x 28=8x-7x+12 28=x+12 28-12=x+12-12 16=x
7X - 19 = 44add 19 to each side7X = 63divide each sides integers by 7X = 9============check in original equation7(9) - 19 = 4463 - 19 = 4444 = 44======checks
x2+7x+12=0 x2+7x=-12 x+Sqaure Root of 7x= 2(SQ Root Symbol)3
5x2+7x = 12 5x2+7x-12 = 0 (5x+12)(x-1) = 0 x = -12/5 or x = 1