To find the product of X and 7X, you multiply the coefficients (numbers in front of the variables) and then multiply the variables together. In this case, 1 (implied coefficient of X) times 7 times X equals 7X^2. So, X times 7X is equal to 7X^2.
The math equation of X times 2 - 7x + 12 times 0 equals 2X - 7x.
To do this equation, you collect like terms. 7x-4x+x-15 is your original equation, you have 3 terms with "'x'" in them, and they are 7x, -4x, and x. 7x + (-4x) +x simplifies to 4x, because 7-4 = 3 + 1 = 4 (the x is really 1x....). After this, you get 4x-15, which is as simplified as this equation can be.
15
x3 + 7x = 8x2x3 + 7x - 8x2 = 0 [subtract 8x2 from both sides]x(x2 + 7 - 8x) = 0 [factor out x]x(x-1)(x-7) = 0 [factor]Since the product of the three factors x, x-1, and x-7 equals zero, any of the three expressions could equal zero:x = 0x - 1 = 0, x = 1x - 7 = 0, x = 7Therefore, there are three solutions to the equation x3 + 7x = 8x2:x = 0x = 1x = 7Or, in set notation: x = {0,1,7}
-8x+7 = -7x-2 -8x = -7x-2-7 -8x=-7x-9 -8x+7x=-9 -1x=-9 x=-9/-1 x=9
If you mean: 7x+91 then it can be factored to 7(x+13)
8x-1 = 7x+2 Add 1 to both sides: 8x = 7x+3 Subtract 7x from both sides: 1x = 3 ie x = 3
1x, 2x, 3x, 4x, 5x, 6x, 7x, 8x, 9x and 10x
x2 × 7x = 7x3
42x
To find the product of X and 7X, you multiply the coefficients (numbers in front of the variables) and then multiply the variables together. In this case, 1 (implied coefficient of X) times 7 times X equals 7X^2. So, X times 7X is equal to 7X^2.
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The math equation of X times 2 - 7x + 12 times 0 equals 2X - 7x.
To do this equation, you collect like terms. 7x-4x+x-15 is your original equation, you have 3 terms with "'x'" in them, and they are 7x, -4x, and x. 7x + (-4x) +x simplifies to 4x, because 7-4 = 3 + 1 = 4 (the x is really 1x....). After this, you get 4x-15, which is as simplified as this equation can be.
If that's +14x + 3, the answer is (2x + 3)(4x + 1)
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