80 = (8 x 10) + (0 x 1)
x2=18x-80 (im guessing you are trying to find x) x2-18x+80=0 (x-10)(x-8)=0 Therefore: x = 10, 8
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If: y = 20 -x and x^2 +y^2 = 80 Then: x^2 +(20-x)^2 = 80 Multiplying out the brackets: x^2 +400 -80x +4x^2 = 80 Transposing terms: 5x^2 +320 -80x = 0 Divide all terms by five: x^2 +64 -16x = 0 Factorizing: (x-8)(x-8) = 0 => x = 8 and x = 8 By substitution point of contact is at: (8, 4)
x2+16x-80 = 0 (x-4)(x+20) = 0 x = 4 or x = -20
80 = (8 x 10) + (0 x 1)
if you meant "x²+7x-80=0"solution1 x≈6solution2 x≈-13if you meant "x²*7x-80=0"x≈2if you meant "x*2*7*x-80=0"solution1 x≈2solution2 x≈-2if you meant "x²+7x-80"unable to find x or simplifyif you meant exactly like you wrote "x*2*7*x-80"then it could be simplified to 14x²-80 but I don't see how to solve this by graphing.
Well, isn't that just a happy little question! To write 80 in expanded form, we break it down into its place values. So, 80 can be written as 8 * 10, showing that it is made up of 8 tens. Remember, there are no mistakes in art or math - just happy little accidents!
x2=18x-80 (im guessing you are trying to find x) x2-18x+80=0 (x-10)(x-8)=0 Therefore: x = 10, 8
Zero.Zip.Zilch.Nada.Nothing.
1020= 1 x 83 + 0 x 82 + 2 x 81 + 0 x 80
6x2 + 58x + 80 = 02(40 + 29x + 3x2) = 02((8 + x)(5 + 3x)) = 0, ignore 28 + x = 0 => x = -85 + 3x = 0 => 3x = 5 => x= 1.666666....x = {-8, 1.66....}
Expanded Notation of 80 = (8 x 101) + (0 x 100).
Two numbers with a difference of 5 have a product of 6800. x and (x + 5) are our numbers. Let's multiply them together. (x) (x+5) = x2 + 5x That is equal to the 6800 specified. x2 + 5x = 6800 >> x2 + 5x - 6800 = 0 (x + 85) (x - 80) = 0 x + 85 = 0, so x = -85 (this in not a correct answer - it has the wrong sign) x - 80 = 0, so x = 80 (a correct answer, and one of the two numbers we need) Since x = 80, x + 5 = 85 Our numbers are 80 and 85. Let's check. 80 times 85 = 6800. Our work checks.
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x*8 - (x>80)?x-80*4:0