x2 = 6482 = 64x = 8
x2 + 2x - 13 = 2 x2 + 2x - 15 = 0 (x + 5)(x - 3) = 0 x + 5 = 0 and x - 3 = 0 so x = -5 and x = 3
x2+36x+120 (x+6)(x+20)
do you mean, x2 = n?? Take the square root.
What are we solving here for, Z, X, or Y?If solve for Z then the answer would be z = x + yIf solve for X then the answer would be z = z - yIf solve for Y than the answer would y = z - xHope this help.
x2+7x+12
x2 plus 3x plus 3 is equals to 0 can be solved by getting the roots.
This is an expression and you do not solve an expression, but you can factor this one.X2 + 3X4X2(1 + 3X2)========
(2x)ysquared
-130
(x+5)^2 and therefore x = -5
x4 - 1.We can not "solve" this as we have not been told the value of x. However, we can simplify this expression:We have an x and a minus x here which will cancel out. Likewise the x2 and x3 will cancel out with the -x2 and -x3 respectively. This therefore leaves us with just x4 - 1.
x2+5x+6 = (x+2)(x+3) when factored because 2 and 3 are factors of 6
(2-r)e-rr
You will need to use the FOIL formula to solve this type of equation.
x=4 x=0
x2 + 4x + 3 = 0 (x + 1)(x + 3) = 0 x ∈ {-3, -1}