13
The volume of this cone is 301.6 units3
All you must do here is take 14 and subtract 6 from it. So r=8.
15 and 24, respectively.
E = I R = (2) (6) = 12 volts
6
13
12 + 8r - 6 = 7r - 5 - 3 8r +6 = 7r -8 r = -14
r=8
If r = 3.25, 8r + 6 = 8(3.25) + 6 = 32.
The volume of this cone is 301.6 units3
All you must do here is take 14 and subtract 6 from it. So r=8.
15 and 24, respectively.
in an equation, it would be used like so in the following example: 5+X*8/X=? if X=6, "plugged in" the problem would be: 5+6*8/6. then just follow your order of operations. your answer would be 14 r. 4
5/6 is greater.
6 R 8
21 4t2+6r-tr 4[-3]2+6[5]-[-3][5] 8[-3]+30-[-15] -24+30+15=21