8^3 (8x8x8) = 512
7^3 (7x7x7) = 343
9^3 (9x9x9) = 729
-9 to the third power = -729(-9)^3 = (-9) * (-9)* (-9)= -729
7/8 x 8/9 = 7/9
It depends: 7/8/9/10 can be: 7/(8/(9/10)) = 7/(80/9) = 63/80, or 7/((8/9)/10) = 7/(8/90) = 7/(4/45) = 315/4 (7/8)/(9/10) = 70/72 = 35/36 (7/(8/9))/10 = (63/8)/10 = 63/80 ((7/8)/9)/10 = (7/72)/10 = 7/720 * * * * * There is an "and" between 8 and 9 so the question, in fact, refers to 7/8 + 9/10 which is not ambiguous. 7/8 + 9/10 = 35/40 + 36/40 = 71/40 = 1 and 31/40
The average of 7, 8, 9, and 4 is 7.
9 to the power of 8 is 9x9x9x9x9x9x9x9=43,046,721
-9 to the third power = -729(-9)^3 = (-9) * (-9)* (-9)= -729
First work out the lowest common multiple of 7, 8 and 9 and then any multiple of this is a common multiple of 7, 8 and 9. The method I use is to list the numbers in their prime factorisation in power format; then the lcm is the product of each prime used to the highest power with which is appears in any of the factorisations. For 7, 8 and 9 this gives: 7 = 7 8 = 2^3 9 = 3^2 lcm = 2^3 x 3^2 x 7 = 504
7/8 x 8/9 = 7/9
(3/9*1)+4+5+7-2-6-8
You are missing the ")" so I can only guess where it should be:7 + 8(3 by the power of 2) - 2 =7 + 8(3²) - 2 =7 + 8 x 3² - 2 =7 + 8 x 9 - 2 =7 + 72 -2 =77 -2 =75
9 to the power of 8 equals 43,046,721
9+9+8+8+7+6=47. I do it this way: (9+9)+(8+8)+(7+6).
I think you have it wrong. Are you trying to ask "why is 6 afraid of 7"? If you are then the answer is because 7 ate (8) 9.
It depends: 7/8/9/10 can be: 7/(8/(9/10)) = 7/(80/9) = 63/80, or 7/((8/9)/10) = 7/(8/90) = 7/(4/45) = 315/4 (7/8)/(9/10) = 70/72 = 35/36 (7/(8/9))/10 = (63/8)/10 = 63/80 ((7/8)/9)/10 = (7/72)/10 = 7/720 * * * * * There is an "and" between 8 and 9 so the question, in fact, refers to 7/8 + 9/10 which is not ambiguous. 7/8 + 9/10 = 35/40 + 36/40 = 71/40 = 1 and 31/40
The average of 7, 8, 9, and 4 is 7.
576
9 to the power of 8 is 9x9x9x9x9x9x9x9=43,046,721