8h+7=-113 -113+7==106/8=h=-13.25 h=-13.25
minus 15.
Assuming 52 work-weeks per year, and 40 hours per week (5 days/week times 8h/day), the figure is 13.7/h.
7 times, with a remainder of 7.
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8h+7=-113 -113+7==106/8=h=-13.25 h=-13.25
h=7
8h - 10h = 3h + 25-2h = 3h + 25-5h = 25-h = 5h = -5
minus 15.
C3H7OH + (9/2)O2 = 3CO2 + 4H2O => 2C3H7OH + 9O2 = 6CO2 + 8H2O Done!!!!!
Assuming 52 work-weeks per year, and 40 hours per week (5 days/week times 8h/day), the figure is 13.7/h.
7 times, with a remainder of 7.
5h+11=13h-21 -5h +21 -5h +21 32=8h /8 /8 4=h
To balance the oxygens, you add H2O to one side, and the H^+ to the other (acid). Example:MnO4^- ===> Mn^2+ add 4 H2O to the right side MnO4^- ===> Mn^2+ + 4H2O this balances the oxygens. Now add 8H^+ to the left side MnO4^- + 8H^+ ===> Mn^2+ + 4H2O Now this is balanced for Mn, H and O. You now only have to balance the electrons (charge).
How do you solve this equation 20h-40=8h+152 ?
h = -5 8h - 10h = 3h + 25 -2h = 3h + 25 -2h - 3h = 3h - 3h + 25 -5h = 25 h = -5 CHECK: 8(-5) - 10(-5) = 3(-5) + 25 -40 - -50 = -15 + 25 -40 + 50 = 10 10 = 10 CORRECT
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