200x
4x3+10x2-6x 2x(2x2+5x-3) 2x(2x-1)(x+3)
6x3+29x2-40x-42 divided by 6x+5 Quotient: x2+4x-10 Remainder: 8
Dividend: 6x^3 +29^2 -40x -42 Divisor: 6x +5 Quotient: x^2 +4x -10 Remainder: 8
2x^2y^3(4x^2 - 3xy + 1)
2(x^2 + 2)(x + 3)
200x
4x3+10x2-6x 2x(2x2+5x-3) 2x(2x-1)(x+3)
6x3+29x2-40x-42 divided by 6x+5 Quotient: x2+4x-10 Remainder: 8
multiply the base number and add the two exponets together
Dividend: 6x^3 +29^2 -40x -42 Divisor: 6x +5 Quotient: x^2 +4x -10 Remainder: 8
2x^2y^3(4x^2 - 3xy + 1)
x² + 4x -10 + 8/(6x+5)in other words 6x+5 doesn't quite divide completely into the original polynomial; it leaves a remainder of 8.Another Answer:-Dividend: 6x^3 +29x^2 -40x -42Divisor: 6x +5Quotient: x^2 +4x -10Remainder: 8
x(x2+5x+6)
(2x - 1)(6x + 5)
This is how I did it:8x3+4x2+6x+3[8x3+4x2]+[6x+3][(4x2)(2x+1)]+[(3)(2x+1)]....as you can see, this is in the general form of ab+cb, which factored is b(a+c), so:(2x+1)(4x2+3)
(4x - 3)(2x + 3)