the form in which you have a base with an exponet.
Well suppose you were asked to pu 6*6*6*6 in an exponet form. You take the number taht wants to be put into exponet form (in this case 6) and the exponet would be how manytimes this munber is multiplied (in this case 4) (the answer would be 6^4)
3^2 x 5
217 = 21 x 31 x 111
If that's the whole problem then the answer would be: m-1 /n (make the -1 an exponet) Or 10 -1 (<- Exponet) / 2 = 0.05 You see the exponet -1 meens basicly the normal exponet only in decimal form Examples: (e meens the next number is the exponet) Normal: 10e1 = 10 Negative: 10e-1 = 0.01 or 1 tenth Normal: 10e2 = 100 Negative: 10e-2 = 0.01 or 1 hundreth Hope this helped!!!
`what is the prime factorization of 100 in exponet form
I
the form in which you have a base with an exponet.
4 with a 5 as its exponet
Well suppose you were asked to pu 6*6*6*6 in an exponet form. You take the number taht wants to be put into exponet form (in this case 6) and the exponet would be how manytimes this munber is multiplied (in this case 4) (the answer would be 6^4)
It is: 22*17 = 68
35 = 51 x 71
3^2 x 5
It is difficult to decipher the question because of all the typographic errors, but the prime (not prim) factorisation (not factorizaionin) exponent (not exponet) form (not from) for 27 is 33
Since '315' ends in '5', a prime number, we can start there. Hence dividing by '5' , and then keep on divising by prime numbers. 5)315 3)63 3)21 7)7 = 1 Always reduce to '1' The factoprs of 315 are 3,3,5,&7. In exponent form 3^(2) X 5^(1) x 7^(1) .
217 = 21 x 31 x 111
If that's the whole problem then the answer would be: m-1 /n (make the -1 an exponet) Or 10 -1 (<- Exponet) / 2 = 0.05 You see the exponet -1 meens basicly the normal exponet only in decimal form Examples: (e meens the next number is the exponet) Normal: 10e1 = 10 Negative: 10e-1 = 0.01 or 1 tenth Normal: 10e2 = 100 Negative: 10e-2 = 0.01 or 1 hundreth Hope this helped!!!