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15y ago

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What is the value of a plus b if a equals 6 and b equals 9?

a = 6b = 9a + b = 6 + 9 = 15


How do you write this as an expression with no parentheses (b plus 3) plus 6?

It is b + 9.


B plus 9 equals 8 plus 6?

Set it up like this: B+9=8+6B+9=14B=5


3a plus 2b - 6 - 2a - b plus 4?

= a + b - 2


IF 2 plus 3 equals 10 7 plus 2 equals 63 6 plus 5 equals 66 8 plus 4 equals 96 THEN 9 plus 7 equals?

The answer is 144. The compound operator for (a) and (b) in each pair is a * (a+b). For 9 and 7, this is 9 x (9+7) = 9 x 16 = 144.


What is the value of a plus b if a equuls 6 and b equls minus 9?

-3


Is absolute value of a and b is equal to the absolute value of a plus the absolute value of b?

Only when a and b have the same sign (or when a or b equals 0). Here are some examples: |2+4|=|2|+|4|--> |6|=|6|--> 6=6 TRUE |(-1)+(-3)|=|(-1)|+|(-3)|--> |(-4)|=1+3--> 4=4 TRUE |3+(-6)|=|3|+|(-6)|--> |(-3)|=3+6--> 3=9 FALSE


If r 9 b 5 and g -6 what does (r plus b - g)(b plus g) equal?

First, substitute the values: ( r = 9 ), ( b = 5 ), and ( g = -6 ). Calculating ( (r + b - g) ) gives ( (9 + 5 - (-6)) = 9 + 5 + 6 = 20 ). Next, calculate ( (b + g) ) as ( (5 + (-6)) = 5 - 6 = -1 ). Finally, multiply the results: ( 20 \times (-1) = -20 ).


12b plus 4 equals 10b plus 16?

b = 6


A plus B equals nine?

4+5=9


What are all the possible values of a and b given that y equals ax plus 14 is the perpendicular bisector of the line joining 1 2 to b 6?

Perpendicular equation: y = ax+14 Slope of line: 2-6/1-b = -1/a Multiply both sides by 1-b: -4 = -1+b/a By trial and improvement: -4 = -1+9/-2 By trial and improvement: -4 = -1-9/2.5 Therefore: a = -2 and b = 9 or a = 2.5 and b = -9


Is b plus 4 a factor of b3 plus 3b2 minus b plus 12?

3 times a times a times b