9 x 1 x 3 = 27
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∙ 8y ago9 = 1 x 9, 3 x 3, 9 x 1
3 x -3 1 x -9 -1 x 9 (1/3)^-2 x -1 etc.
The answer is 1. X=(3)^2 * (3)^-2 X=(3)^2 * 1/(3)^2 X=9 * 1/9 X=9/9 X=1
-2x+9=x+1-x........-x-3x+9=1.....-9...-9-3x=-8-3x/-3 | -8/-3\ /........\ /x=8/3
9 as it is 3 x 3 and also 1 x 9
factors of 9 are 1, 3 and 9
1, 3, 9 3 x 3 = 9 1 x 9 = 9 9 x 1 = 9
9 = 1 x 9, 3 x 3, 9 x 1
9 times 3 equals 27.
1 x 9, 3 x 3, 9 x 1 = 9
The factor pairs of 9 are (1, 9) and (3, 3)
1 x 63, 3 x 21, 7 x 9, 9 x 7, 21 x 3, 63 x 1.
1/3 x 9 = 3
9 is written 9/1 9/1 x 4/3 9 x 4 = 36 1 x 3 = 3 36/3 reduced is 12/1 = 12
3x2 + 2x + 2 = 0 Can not be factored. You can however solve it for x: 3x2 + 2x = -2 x2 + 2x/3 = -2/3 x2 + 2x/3 + 1/9 = -2/3 + 1/9 (x + 1/9)2 = -5/9 x + 1/9 = ±√(-5/9) x = -1/9 ± i√(5/9) x = -1/9 ± i√5 / 3 x = -1/9 ± 3i√5 / 9 x = (-1 ± 3i√5) / 9
1 x 9, 3 x 3, 9 x 1 = 9
1 x 9, 3 x 3