AREA = A = 1/2 (b1 + b2)(h) h= height = 2(A) / (b1 + b2)
((B1+B2)/2)*h=A B1 and B2 are "Base 1" and "Base 2" (the parallel sides) h is the height A is, of course, the area
area= 1/2 h (b1+b2) h=heigth b1 and b2=base 1 and base 2
H(b1+ b2)/ 2
A = 1/2 (b1 + b2) h b1 = base 1 (usually the bottom) b2 = base 2 (usually the top) h = height
AREA = A = 1/2 (b1 + b2)(h) h= height = 2(A) / (b1 + b2)
((B1+B2)/2)*h=A B1 and B2 are "Base 1" and "Base 2" (the parallel sides) h is the height A is, of course, the area
area= 1/2 h (b1+b2) h=heigth b1 and b2=base 1 and base 2
Answer: No.Explanation: Area of trapezoid = 1/2(b1 + b2) * h where b1 is length of base one, b2 is length of base 2 and h is height.this equation = 1/2*b1*h + 1/2*b2*hdouble one base:1/2(2*b1+b2) *h = b1*h+1/2*b2*h = (b1+1/2*b2)*hin order for the area to double, both bases would have to double which would cancel out both 1/2's. Only one is cancelled out so the area would increase but not double
H(b1+ b2)/ 2
A = 1/2 (b1 + b2) h b1 = base 1 (usually the bottom) b2 = base 2 (usually the top) h = height
1/2 of (B1+B2)H
A = 1/2(b1 + b2)h
a=1/2(b1+b2)*h
Probably nothing, since I suspect that it is incorrect. It could be the formula for 2 times the area of a trapezium, where A = Area b1 and b2 are the lengths of the parallel sides and h is the vertical distance (height) between them.
if the bases are b1 and b2, then: area = ½ × (b1 + b2) × h → 2 × area ÷ h = b1 + b2 → b2 = 2 × area ÷ h - b1 = 2 × 156.6 m² ÷ 18 m - 6 m = 11.4 m
A= 1/2 (b1+b2) h