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Why does the definition of rational numbers state that b the denominator of the rational number ab cannot be equal?
I think it says a little more than that. b, the denominator of the rational number a/b, cannot be equal to zero because division by zero is undefined.
How do you change a mixed number to a imprper fraction?
A mixed number of the form AB/C, as an improper fraction, is equal to (AC + B)/CA mixed number of the form AB/C, as an improper fraction, is equal to (AC + B)/CA mixed number of the form AB/C, as an improper fraction, is equal to (AC + B)/CA mixed number of the form AB/C, as an improper fraction, is equal to (AC + B)/C
Why does b times ab equal ab squared and not equal ab plus b squared?
b*ab = ab2 Suppose b*ab = ab + b2. Assume a and b are non-zero integers. Then ab2 = ab + b2 b = 1 + b/a would have to be true for all b. Counter-example: b = 2; a = 3 b(ab) = 2(3)(2) = 12 = ab2 = (4)(3) ab + b2 = (2)(3) + (2) = 10 but 10 does not = 12. Contradiction. So it cannot be the case that b = 1 + b/a is true for all b and, therefore, b*ab does not = ab + b2
In trapezium ABC AB and DC are parallel sides and AB equal 5cm CD equal 7.5cm and AB equal 6cm Draw BX parallel AD to cut CD at X Find angle BCX and BD?
The question cannot be answered since it is inconsistent. It first states that AB equals 5 cm and then AB equals 6 cm. Please check your typing and resubmit.
What is The set of numbers expressed in the form of a fraction ab where a and b are integers and b can't equal zero?
It is the set of rational numbers.
Why does the definition of rational numbers state that b the denominator of the rational number ab cannot be equal?
I think it says a little more than that. b, the denominator of the rational number a/b, cannot be equal to zero because division by zero is undefined.
A number that can be written in the form ab where a and b are integers and the denominator is not equal to zero?
Repeating decimal
What number is pie equal to?
ab Link
How do you change a mixed number to a imprper fraction?
A mixed number of the form AB/C, as an improper fraction, is equal to (AC + B)/CA mixed number of the form AB/C, as an improper fraction, is equal to (AC + B)/CA mixed number of the form AB/C, as an improper fraction, is equal to (AC + B)/CA mixed number of the form AB/C, as an improper fraction, is equal to (AC + B)/C
Why does b times ab equal ab squared and not equal ab plus b squared?
b*ab = ab2 Suppose b*ab = ab + b2. Assume a and b are non-zero integers. Then ab2 = ab + b2 b = 1 + b/a would have to be true for all b. Counter-example: b = 2; a = 3 b(ab) = 2(3)(2) = 12 = ab2 = (4)(3) ab + b2 = (2)(3) + (2) = 10 but 10 does not = 12. Contradiction. So it cannot be the case that b = 1 + b/a is true for all b and, therefore, b*ab does not = ab + b2
Find two square matrices A and B neither of which are zero such that AB equal to 0?
yes that's absoloutly correct
In trapezium ABC AB and DC are parallel sides and AB equal 5cm CD equal 7.5cm and AB equal 6cm Draw BX parallel AD to cut CD at X Find angle BCX and BD?
The question cannot be answered since it is inconsistent. It first states that AB equals 5 cm and then AB equals 6 cm. Please check your typing and resubmit.
What is The set of numbers expressed in the form of a fraction ab where a and b are integers and b can't equal zero?
It is the set of rational numbers.
What does ab equals 1a plus 1B plus ab equal to?
ab=1a+1b a is equal to either 0 or two, and b is equal to a
What is ab over negative three equal?
It's -(ab/3) . The actual number that it is depends on the values of 'a' and 'b'. As soon as either of them changes, -(ab/3) also immediately changes.
What is an equation in the form ab equals CD that states that two ratios are equal?
If a, b, c and d are all non-zero then ab = CD if and only if a/c = d/b or (equivalently) a/d = b/c
How do you prove zero is a number?
You always need to start with something when doing math, most people use a set of axioms known as Peano axioms. The 5th one says 0 is a natural number. These axioms are the basis of math as we now know it. They are the things we assume to be true. Answer 2: Prove existence of zero Suppose, to the contrary that zero does not exist. Further suppose that a=b. Then: ab = b^2 a^2 - ab = a^2 - b^2 a( a - b ) = (a+b)(a-b). Now, since we supposed that zero does not exist, (a-b) must be equal to some number other than zero. Therefore, a = (a+b) (We divide both sides by a-b, which, by supposition, is a non-zero number). a = (a+a) (a=b, We supposed that a=b is a given) 1a = 2a 1 = 2. We have 1=2, an obvious contradiction, therefore, zero does exist.
