That's close to the definition of a rational number.
I think it says a little more than that. b, the denominator of the rational number a/b, cannot be equal to zero because division by zero is undefined.
A mixed number of the form AB/C, as an improper fraction, is equal to (AC + B)/CA mixed number of the form AB/C, as an improper fraction, is equal to (AC + B)/CA mixed number of the form AB/C, as an improper fraction, is equal to (AC + B)/CA mixed number of the form AB/C, as an improper fraction, is equal to (AC + B)/C
b*ab = ab2 Suppose b*ab = ab + b2. Assume a and b are non-zero integers. Then ab2 = ab + b2 b = 1 + b/a would have to be true for all b. Counter-example: b = 2; a = 3 b(ab) = 2(3)(2) = 12 = ab2 = (4)(3) ab + b2 = (2)(3) + (2) = 10 but 10 does not = 12. Contradiction. So it cannot be the case that b = 1 + b/a is true for all b and, therefore, b*ab does not = ab + b2
A number that can be expressed in the form ( ab ), where ( a ) and ( b ) are integers and ( b \neq 0 ), is known as an integer multiple of ( a ). This representation highlights that the number is the result of multiplying ( a ) by a non-zero integer ( b ). Such numbers can be positive or negative, depending on the values of ( a ) and ( b ). Examples include ( 4 ) (where ( a = 4 ) and ( b = 1 )) and ( -6 ) (where ( a = -2 ) and ( b = 3 )).
The question cannot be answered since it is inconsistent. It first states that AB equals 5 cm and then AB equals 6 cm. Please check your typing and resubmit.
I think it says a little more than that. b, the denominator of the rational number a/b, cannot be equal to zero because division by zero is undefined.
Repeating decimal
If AB does not equal 3x, then AB must either be less than 3x or greater than 3x. This means we can express the relationship as AB < 3x or AB > 3x. The statement highlights that AB cannot be equal to 3x by definition.
ab Link
A mixed number of the form AB/C, as an improper fraction, is equal to (AC + B)/CA mixed number of the form AB/C, as an improper fraction, is equal to (AC + B)/CA mixed number of the form AB/C, as an improper fraction, is equal to (AC + B)/CA mixed number of the form AB/C, as an improper fraction, is equal to (AC + B)/C
b*ab = ab2 Suppose b*ab = ab + b2. Assume a and b are non-zero integers. Then ab2 = ab + b2 b = 1 + b/a would have to be true for all b. Counter-example: b = 2; a = 3 b(ab) = 2(3)(2) = 12 = ab2 = (4)(3) ab + b2 = (2)(3) + (2) = 10 but 10 does not = 12. Contradiction. So it cannot be the case that b = 1 + b/a is true for all b and, therefore, b*ab does not = ab + b2
A number that can be expressed in the form ( ab ), where ( a ) and ( b ) are integers and ( b \neq 0 ), is known as an integer multiple of ( a ). This representation highlights that the number is the result of multiplying ( a ) by a non-zero integer ( b ). Such numbers can be positive or negative, depending on the values of ( a ) and ( b ). Examples include ( 4 ) (where ( a = 4 ) and ( b = 1 )) and ( -6 ) (where ( a = -2 ) and ( b = 3 )).
yes that's absoloutly correct
The question cannot be answered since it is inconsistent. It first states that AB equals 5 cm and then AB equals 6 cm. Please check your typing and resubmit.
It is the set of rational numbers.
ab=1a+1b a is equal to either 0 or two, and b is equal to a
It's -(ab/3) . The actual number that it is depends on the values of 'a' and 'b'. As soon as either of them changes, -(ab/3) also immediately changes.