0
b*ab = ab2
Suppose b*ab = ab + b2. Assume a and b are non-zero integers. Then
ab2 = ab + b2
b = 1 + b/a would have to be true for all b.
Counter-example:
b = 2; a = 3
b(ab) = 2(3)(2) = 12 = ab2 = (4)(3)
ab + b2 = (2)(3) + (2) = 10
but 10 does not = 12. Contradiction. So it cannot be the case that b = 1 + b/a is true for all b and, therefore, b*ab does not = ab + b2
What else can I help you with?
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-2a^2
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(a + x^2)(b + y^2)
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b2 + ab - 2 - 2b2 + 2ab = -b2 + ab - 2 which cannot be simplified further.
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4
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