The cyclist ends up 1 mile east of the starting point (unless the cycling takes place near the north or south pole!). So the displacement is 1 mile in an easterly direction.
5 miles minus 4 miles is 1 mile East of the starting point. Displacement is a vector quantity, so it must have magnitude and direction.
No. Distance is never negative, and total distance travelled doesn't decrease during a trip. The distance from A to B is the same as the distance from B to A. Displacement, on the other hand, can be negative, and can decrease during a trip. The displacement from A to B is the same magnitude, but opposite sign, as the displacement from B to A. An example would be if you went from your home to a friend's house 1 mile to the east. After you reach your friend's house, you have travelled a distance of 1 mile and your displacement from your starting position is 1 mile. When you come back home from your friends house, you travel a distance of 1 more mile. Your total distance travelled is now 2 miles, but your displacement from your starting location is zero (because you are back where you started.)
There is one - the north pole. Note that you could go 1 mile south, 1 mile west, and one mile back north to end up on the north pole where you began your trip.Similarly, you could do the opposite directions from the south pole. Go 1 mile north, then 1 mile east or west, and go 1 mile back south to end up on the south pole again.(Note that moving E or W from a point near the poles involves a curved path rather than a straight line.)No, there are an infinite number. At any point on the circle that is 1+1/(2 x pi) miles from the south pole, you can go 1 mile south, 1 mile west will do a complete circuit of the South pole and get you back to where you were after the South leg, and then 1 mile North will get you back to where you started.And at any point on the circle that is 1 + 1/(4 x pi) miles from the South Pole, you can go 1 mile South, 1 mile west will do 2 laps around the pole, and 1 mile North will take you back to where you started ... etc.
Yes but also 2 miles by half a mile 10 miles by 1/10th a mile etc
1 mile East
The cyclist ends up 1 mile east of the starting point (unless the cycling takes place near the north or south pole!). So the displacement is 1 mile in an easterly direction.
5 miles minus 4 miles is 1 mile East of the starting point. Displacement is a vector quantity, so it must have magnitude and direction.
The Pulse Nightclub is located on the corner of West Ester Street and South Orange Avenue. It's around half a mile east of I-4 and a bit over a mile south of highway 408. It's northeast of Lake Holden and due south of Lake Cherokee. It's around 3 miles northwest of the Orlando Airport.
1 mile
The resultant displacement would be the diagonal of a right triangle with sides of 1 mile and 12 miles. If we label the 1 mile as vector a and the 12 mile as vector b, the resultant displacement (vector c) would be the hypotenuse of the triangle formed by vectors a and b.
How about you do your own homework, and in particular that which requires drawing which we can't do here, instead?I don't even think I could describe what to draw in terms any simpler than the question itself.
There's no city there. That point is about 0.81 mile south of Pinery Rd and 1.44 miles east of Rosedale Rd N, 7 miles north-northeast of the center of Smiths Falls, Ontario. It's about 32.7 miles southwest of the center of Ottawa.
Denver Colorado is known as the Mile High City.
140 miles down I-71 SOUTH.
10 miles South East of Harrisburg, in Middletown
1 nautical mile northeast of the town of Prestwick in South Ayrshire and 32 mi from the city centre of Glasgow.