After a thorough search, I have found nothing called El pi. Perhaps the person asking the question means what is Pi? In that case, it is a mathematical constant calculated by the ratio of a circle's circumference to its diameter. It is equal approximately to the value 3.14159.
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by euler: i=ei(pi)/2 therifore ii = (ei(pi)/2)i=ei^2(pi)/2=e-(pi)/2 ~0.208
No. Say your matrix is called A, then a number e is an eigenvalue of A exactly when A-eI is singular, where I is the identity matrix of the same dimensions as A. A-eI is singular exactly when (A-eI)T is singular, but (A-eI)T=AT-(eI)T =AT-eI. Therefore we can conclude that e is an eigenvalue of A exactly when it is an eigenvalue of AT.
[pi^(1/3)]^2 * pi = pi^(2/3) * pi = pi^(5/3) The answer is the cubic root of pi to the fifth power.
(pi + pi + pi) = 3 pi = roughly 9.4248 (rounded) Well, if you use the common shortened version of pi which is 3.14 and add that 3 times, you get 9.42.
(cos(pi x) + sin(pi y) )^8 = 44 differentiate both sides with respect to x 8 ( cos(pi x) + sin (pi y ) )^7 d/dx ( cos(pi x) + sin (pi y) = 0 8 ( cos(pi x) + sin (pi y ) )^7 (-sin (pi x) pi + cos (pi y) pi dy/dx ) = 0 8 ( cos(pi x) + sin (pi y ) )^7 (pi cos(pi y) dy/dx - pi sin (pi x) ) = 0 cos(pi y) dy/dx - pi sin(pi x) = 0 cos(pi y) dy/dx = sin(pi x) dy/dx = sin (pi x) / cos(pi y)