2f + 8 = 103 2f = 95 f = 47.5
-6 plus 2f plus 3f equals 29 -6 + 2f + 3f = 29 -6 + 5f = 29 5f = 35 f = 7
2f plus 3e
11
5f-2
Denoting ff as f2 etc, f2 + f + f3 + f = f3 + f2 + 2f
The question contains an expression but not an equation nor inequality. There is therefore, nothing that can be solved.
2f + 8 = 103 2f = 95 f = 47.5
-6 plus 2f plus 3f equals 29 -6 + 2f + 3f = 29 -6 + 5f = 29 5f = 35 f = 7
f^2 + 2f = f (f + 2)
2f plus 3e
The coefficient for F2 in the chemical equation Ca + F2 → CaF2 is 1.
It is an expression that can be simplified to: 13e+9f
F2 < F2- < F2+. This is because F2 has no extra electrons or missing electrons, while F2- has an extra electron making it more stable than F2. F2+ is the least stable as it has lost an electron, creating an electron deficiency.
2f + 8 = 102 Subtract 8 from both sides: 2f = 94 Divide both sides by 2: f = 47
Simplified is 5e-2f.
It is an equation in one variable.