The question contains an expression but not an equation nor inequality. There is therefore, nothing that can be solved.
Denoting ff as f2 etc, f2 + f + f3 + f = f3 + f2 + 2f
4(f2 - g) + (f2 + 2g) which can be expanded and simplified to 5f2 - 2g
Its already balanced.
Following logic for Fibonocci int f1=0; intf2=1; int i=0; while(i
The Fibonacci sequence has this form: Fn + 2 = Fn + 1 + Fn with these starting values F0 = 0 and F1 = 1. Find the 7th term via similar computation by substituting the values in! You should get... F2 = F1 + F0 F2 = 1 + 0 F2 = 1 F3 = F2 + F1 F3 = 1 + 1 F3 = 2 F4 = 3 F5 = 5 F6 = 8 F7 = 13 So the 7th term of the Fibonacci sequence is 13.
Denoting ff as f2 etc, f2 + f + f3 + f = f3 + f2 + 2f
4f it doesn't matter if the letter is capitalized or not it's still the same letter and it doesn't matter if 'f' is in front or behind
4(f2 - g) + (f2 + 2g) which can be expanded and simplified to 5f2 - 2g
2.
F2+ most stable>f2>f2-
Of these choices:a. Ca(s) + F2(g) → CaF2(s)b. Ca(g) + F2(g) → CaF2(s)c. Ca2+(g) + 2F−(g) → CaF2(s)d. Ca(g) + 2F(g) → CaF2(s)
the answer is 1
Such elements, borrowing electrons, are called 'electron acceptors' or in other words 'oxidants'.The strongest elemental oxidant is Fluorine, F2:F2 + 2e- --> 2F-
Single replacement. The F2 replaces Cl to form HF and Cl2.
Its already balanced.
yes, because it stinks! LOL haha
Single replacement.