f(x) = x2 + 3x - 2 then f'(x) = 2x + 3 and then then f'(2) = 2*2 + 3 = 4+3 = 7
A cubic function, continuous, differentiable.
Are you trying to solve for x? Fx = x2 - 3 x2 - Fx - 3 = 0 x2 - Fx = 3 x2 - Fx + (F/2)2 = 3 + (F/2)2 (x - F/2)2 = 3 + (F/2)2 x - F/2 = ±[ 3 + (F/2)2 ]1/2 x = F/2 ± [ 3 + (F/2)2 ]1/2
It is [(2a+2h+5) - (2a+5)]/h = 2h/h = 2
Using the remainder theorem:- The function of x becomes f(-2) because the divisor is x+2 Substitute -2 for x in the dividend: 2x3+x-7 When: f(-2) = 2(-2)3+(-2)-7 = -25 Then: -25 is the remainder
f(x) = x2 + 3x - 2 then f'(x) = 2x + 3 and then then f'(2) = 2*2 + 3 = 4+3 = 7
find f'(x) and f '(c)f(x) = (x^3-3x)(2x^2+3x+5
A cubic function, continuous, differentiable.
-2, 1.74 and 0.46
Are you trying to solve for x? Fx = x2 - 3 x2 - Fx - 3 = 0 x2 - Fx = 3 x2 - Fx + (F/2)2 = 3 + (F/2)2 (x - F/2)2 = 3 + (F/2)2 x - F/2 = ±[ 3 + (F/2)2 ]1/2 x = F/2 ± [ 3 + (F/2)2 ]1/2
Unfortunately, limitations of the browser used by Answers.com means that we cannot see most symbols. It is therefore impossible to give a proper answer to your question. Please resubmit your question spelling out the symbols as "plus", "minus", "equals", "squared", "cubed" etc. It is not clear whether f(x) = [(x - 2)*(x - 6)3] + 12 or f(x) = (x - 2)*[(x - 6)3 + 12] or something else.
There is no such grade as F minus. When someone gets an F on a test or their report card, they have failed the test or class, and they cannot get any lower than this failure.
3-e = 4-f f-e = 4-3 f-e = 1
2 degrees Fahrenheit minus 5 degrees Fahrenheit is equal to -3 degrees Fahrenheit.
It is [(2a+2h+5) - (2a+5)]/h = 2h/h = 2
Silence is golden
Using the remainder theorem:- f(x) = 4x3+6x2+3x+2 f(x) becomes f(-3/2) or f(-1.5) because the divisor is 2x+3 f(-1.5) = 4(-1.5)3+6(-1.5)2+3(-1.5)+2 = -5/2 or -2.5 So the remainder is -2.5