4(x + 6) = 56
x = 8
Let's call the unknown number x. We can set up the equation as 4(6 + x) = 56. By distributing the 4, we get 24 + 4x = 56. Subtracting 24 from both sides gives us 4x = 32. Finally, dividing both sides by 4 gives us x = 8. Thus, the unknown number is 8.
The sum of number and four times a number is 25 write in algebraic expression
90
4x+5x
Call your number some variable, for example, "n". Twice the number would be 2n, adding four to that you get 2n + 4, and six times all that is 6(2n + 4), which is the same as 12n + 24.
Four times the unknown number. Let's say the unknown number is x. x + 3x = 4x
4N + 8
The sum of number and four times a number is 25 write in algebraic expression
90
2x+4y
4x+5x
6x + 4 = 5x x = -4
Suppose the number is x. The sum of the number and two is x+2 Four times the sum is 4(x+2) The number times 8 is 8x 24 less than the number times 8 is 8x-24 4(x+2) = 8x-24 4x+8=8x-24 so 4x = 32 and x = 8
Call your number some variable, for example, "n". Twice the number would be 2n, adding four to that you get 2n + 4, and six times all that is 6(2n + 4), which is the same as 12n + 24.
The larger number is 12.
Four times the unknown number. Let's say the unknown number is x. x + 3x = 4x
2x3=6+4=10 2.
4(n+12)