What is NxNxN?

What is the time complexity of an algorithm when the keyword "nxnxn" is considered?

The time complexity of an algorithm when the keyword "nxnxn" is considered is O(n3), where n represents the input size.

What is the number sequence 1 8 27 64?

Cubes of digits 1 - 4n3. (nxnxn) 13 = 1, 23 = 8, 33 = 27...1x1x1 = 12x2x2 = 83x3x3 = 274x4x4 = 645x5x5 = 1256x6x6 = 216

What is cube of number?

if you are talking about squaring then that means to multiplt the base number by iself like this 72= 7*7= 49 But we are not talking about squaring. The cube of a number N, is NxNxN so 5 cubed is 5x5x5=125

If you have the volume of a cube how do you calculate the dimensions?

Take the cube root of that number. For example, volume is 8 square inches and the cube root of 8 is 2. In case you forgot, if N is the Cube root of a number M then NxNXN=M

Is a negative timesa negative times a negative a positive or a negative?

A negative times a negative times a negative (NxNxN) is a : Negative!!! Negative times a negative is positive. A positive times a negative is a negative. Remember if you are multiplying an odd number of negatives irrespective of the number of positives, it is always a negative. If you are multiplying an even number of negatives then the answer is a positive. EX: -2 x -1 x -2 ( 3 negatives so answer is negative) 2 x -2 -4 -3x-5x-1x-1x2x1 ( 4 negatives so answer is positive) 15x1x2 30

Why does any number to the zero power equal one?

Here is why any number to the zero power equals one. Consider this. a^b. it is natural to restrict a > 0, but we'll only assume that number b is any real number. We'll use the natural exponential function defined by the derivative of the exponential function. Now we have a^r=e^rln(a). And we know that e^rln(a)=e^((ln(a))^r), where a >0 and r is in the domain of all real numbers negative infinity to infinity. We can apply this definition to any number a to any power r. Particularly, a^0. By the provided definition, a^0=e^(0*ln(a))=e^0=1. Furthermore, a^1=e^(1*ln(a))=e(ln(a))=a. And a^2=(e^(ln(a))^2)=a^2. ---------------------------------- Here is a simpler approach: In general, a^n/a^m = a^(n-m) and a/a = 1. We can use these facts to prove that x^0 = 1 so long as x isn't 0. First, state the obvious: 1 = 1 Next, since any non-zero number divided by itself is one: 1 = a^n/a^n (It doesn't change how the equation looks, but for the sake of being thorough, you could subsitute (a^n/a^n) in place of 1 in the original equation.) Then, since dividing like bases requires that you subtract their exponents: a^n/a^n = a^(n-n) = a^0 Substitute (a^0) in for (a^n/a^n) and you obtain: a^0 = 1 There are two reasons "a" cannot be 0 in this proof: firstly, raising 0 to non-zero powers would still result in zero, so "a" being 0 would cause division by zero in the initial theorems we used, and secondly, 0^0 is considered undefined in itself.

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Add your answer:

What is cube of number?

If you have the volume of a cube how do you calculate the dimensions?

What is the time complexity of an algorithm when the keyword "nxnxn" is considered?

What is the number sequence 1 8 27 64?

What is cube of number?

If you have the volume of a cube how do you calculate the dimensions?

Is a negative timesa negative times a negative a positive or a negative?

Why does any number to the zero power equal one?

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