It can be just about anything, depending on the values assigned to the variables ("r" and "n").
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P(n,r)=(n!)/(r!(n-r)!)This would give you the number of possible permutations.n factorial over r factorial times n minus r factorial
The number of R-combinations in a set of N objects is C= N!/R!(N-R)! or the factorial of N divided by the factorial of R and the Factorial of N minus R. For example, the number of 3 combinations from a set of 4 objects is 4!/3!(4-3)! = 24/6x1= 4.
The expression n2 - n - 56 factors to (n - 8)(n + 7).
n p =n!/(n-r)! r and n c =n!/r!(n-r)! r
The value of 6 minus n depends on the value of n and cannot be answered until known. Once n is known, subtract it from 6 to get your answer.