answersLogoWhite

0

What is R minus N?

Updated: 12/16/2022
User Avatar

Wiki User

10y ago

Best Answer

It can be just about anything, depending on the values assigned to the variables ("r" and "n").

User Avatar

Wiki User

10y ago
This answer is:
User Avatar

Add your answer:

Earn +20 pts
Q: What is R minus N?
Write your answer...
Submit
Still have questions?
magnify glass
imp
Related questions

An algorithm that generates all r-permutations of an n-element set?

P(n,r)=(n!)/(r!(n-r)!)This would give you the number of possible permutations.n factorial over r factorial times n minus r factorial


Prove that nCr plus nCr minus 1 equals n plus 1Cr?

nCr + nCr-1 = n!/[r!(n-r)!] + n!/[(r-1)!(n-r+1)!] = n!/[(r-1)!(n-r)!]*{1/r + 1/n-r+1} = n!/[(r-1)!(n-r)!]*{[(n-r+1) + r]/[r*(n-r+1)]} = n!/[(r-1)!(n-r)!]*{(n+1)/r*(n-r+1)]} = (n+1)!/[r!(n+1-r)!] = n+1Cr


What is Negative two n plus seven n minus r plus ten r?

It is 5n + 9r.


How can you Find the number of combinations of objects in a set?

The number of R-combinations in a set of N objects is C= N!/R!(N-R)! or the factorial of N divided by the factorial of R and the Factorial of N minus R. For example, the number of 3 combinations from a set of 4 objects is 4!/3!(4-3)! = 24/6x1= 4.


What is n squared minus n?

n squared minus n


How do you factor n square minus n minus 56?

The expression n2 - n - 56 factors to (n - 8)(n + 7).


What is 2 minus n minus 7n?

2-n-7n = 2-8n


How do you write n-5 as a algebraic expression in words?

n minus five five subtracted from n


What is the difference between a permutation and combination?

n p =n!/(n-r)! r and n c =n!/r!(n-r)! r


What is 6 minus n?

The value of 6 minus n depends on the value of n and cannot be answered until known. Once n is known, subtract it from 6 to get your answer.


Why is it said that poisson distribution is a limiting case of binomial distribution?

This browser is totally bloody useless for mathematical display but...The probability function of the binomial distribution is P(X = r) = (nCr)*p^r*(1-p)^(n-r) where nCr =n!/[r!(n-r)!]Let n -> infinity while np = L, a constant, so that p = L/nthenP(X = r) = lim as n -> infinity of n*(n-1)*...*(n-k+1)/r! * (L/n)^r * (1 - L/n)^(n-r)= lim as n -> infinity of {n^r - O[(n)^(k-1)]}/r! * (L^r/n^r) * (1 - L/n)^(n-r)= lim as n -> infinity of 1/r! * (L^r) * (1 - L/n)^(n-r) (cancelling out n^r and removing O(n)^(r-1) as being insignificantly smaller than the denominator, n^r)= lim as n -> infinity of (L^r) / r! * (1 - L/n)^(n-r)Now lim n -> infinity of (1 - L/n)^n = e^(-L)and lim n -> infinity of (1 - L/n)^r = lim (1 - 0)^r = 1lim as n -> infinity of (1 - L/n)^(n-r) = e^(-L)So P(X = r) = L^r * e^(-L)/r! which is the probability function of the Poisson distribution with parameter L.


What is n minus 10 plus 9n minus 3?

n - 10 + 9n - 3 = 10n - 13