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What is the Value of 3t plus 5 given that -7t-2 equals 5?
2 (t = -1)
What does t equal if -t equals 5?
If -t = 5, then t = -5
What is t if 5 times t minus 5 over -10 equals 70?
Depends on which question you're asking: 1) (5t-5)/-10=70 5t-5=-700 5t=-695 t=-139 2) (5(t-5))/-10=70 5(t-5)=-700 5t-25=-700 5t=-675 t=-135
What is the answer to 8t plus 5 equals 6t plus 1?
t=-2
How do you solve t plus 9 equals -5?
4
Evaluate t-7over w for t equals -3 and w equals -2?
To evaluate t-7 over w for t equals -3 and w equals -2, we substitute -3 for t and -2 for w in the expression. This gives us (-3) - 7 over (-2), which simplifies to -10 over -2. Further simplifying, we get 5 as the final result.
What is the Value of 3t plus 5 given that -7t-2 equals 5?
2 (t = -1)
What does t equal if -t equals 5?
If -t = 5, then t = -5
What is t if 5 times t minus 5 over -10 equals 70?
Depends on which question you're asking: 1) (5t-5)/-10=70 5t-5=-700 5t=-695 t=-139 2) (5(t-5))/-10=70 5(t-5)=-700 5t-25=-700 5t=-675 t=-135
What is the answer to 8t plus 5 equals 6t plus 1?
t=-2
If y equals x cube plus 2x and dx over dt equals 5 what is dy over dt when x equals 2?
y=x3+ 2x, dx/dt=5, x=2, dy/dt=? Differentiate the equation with respect to t. dy/dt=3x2*dx/dt Substitute in known values. dy/dt=3(2)2 * (5) dy/dt=60
What is the period of xt equals 3.4 Cos5 Pi t - Pi?
Assuming the question refers to x(t) = 3.4*cos(5*pi*t) - pi, the periodicity of the cos function is 2*pi So 5*pi*t = 2*pi or 5*t = 2 or t = 0.4
How do you solve t plus 9 equals -5?
4
What is sec theta if sin theta equals 2 over 3 with theta in quadrant 1?
sin(t) = 2/3 sin2(t) + cos2(t) = 1 so cos(t) = ± sqrt[1 - sin2(t)] but because t is in the first quadrant, cos(t) > 0 so cos(t) = + sqrt[1 - sin2(t)] = sqrt[1 - 4/9] = sqrt[5/9] = sqrt(5)/3 Then sec(t) = 1/cos(t) = 1/sqrt(5)/3 = 3/sqrt(5) = 3*sqrt(5)/5
Find s when t equals 10 if s is inversely proportional to t and s equals 100 when t equals 5?
50
What was jack's speed from t equals 5 sec to t equals 10 sec?
Jack's speed from t=5 seconds to t=10 seconds is the average speed over that time interval. You can calculate this by finding the total distance traveled during that time period and dividing it by the time taken.
2 equals it t to t?
It Takes 2 to Tango
