2 (t = -1)
If -t = 5, then t = -5
Depends on which question you're asking: 1) (5t-5)/-10=70 5t-5=-700 5t=-695 t=-139 2) (5(t-5))/-10=70 5(t-5)=-700 5t-25=-700 5t=-675 t=-135
t=-2
4
To evaluate t-7 over w for t equals -3 and w equals -2, we substitute -3 for t and -2 for w in the expression. This gives us (-3) - 7 over (-2), which simplifies to -10 over -2. Further simplifying, we get 5 as the final result.
If -t = 5, then t = -5
2 (t = -1)
Depends on which question you're asking: 1) (5t-5)/-10=70 5t-5=-700 5t=-695 t=-139 2) (5(t-5))/-10=70 5(t-5)=-700 5t-25=-700 5t=-675 t=-135
t=-2
y=x3+ 2x, dx/dt=5, x=2, dy/dt=? Differentiate the equation with respect to t. dy/dt=3x2*dx/dt Substitute in known values. dy/dt=3(2)2 * (5) dy/dt=60
Assuming the question refers to x(t) = 3.4*cos(5*pi*t) - pi, the periodicity of the cos function is 2*pi So 5*pi*t = 2*pi or 5*t = 2 or t = 0.4
4
sin(t) = 2/3 sin2(t) + cos2(t) = 1 so cos(t) = ± sqrt[1 - sin2(t)] but because t is in the first quadrant, cos(t) > 0 so cos(t) = + sqrt[1 - sin2(t)] = sqrt[1 - 4/9] = sqrt[5/9] = sqrt(5)/3 Then sec(t) = 1/cos(t) = 1/sqrt(5)/3 = 3/sqrt(5) = 3*sqrt(5)/5
50
Jack's speed from t=5 seconds to t=10 seconds is the average speed over that time interval. You can calculate this by finding the total distance traveled during that time period and dividing it by the time taken.
It Takes 2 to Tango