To find the solution to the equation √(x-10) = x-2, we can square both sides. This gives us x-10 = (x-2)^2. Expanding the right side gives x-10 = x^2 - 4x + 4. Rearranging the terms and simplifying, we have x^2 - 5x - 6 = 0. By factoring or using the quadratic formula, we can determine the solution(s) to the equation.
Plus or minus the base. If the base is X and you square it, you get X2. If you take the square root of that, you get Plus or Minus X. This is because X*X equals X2 and -X*-X also equals X2.
34
x2-10 = 0 x2 = 10 x = the square root of 10
Take the square root of both sides. x=the square root of 10. It is an irrational number. Approximately 3.15
x2+3=124 x2=121 x= square root(121) x=11
Plus or minus the base. If the base is X and you square it, you get X2. If you take the square root of that, you get Plus or Minus X. This is because X*X equals X2 and -X*-X also equals X2.
34
If: x2 = 3 Then: x = square root of 3
x2-10 = 0 x2 = 10 x = the square root of 10
x2 = 81 Square root both sides:- x = +/- 9
if you mean X²+8X-5=0: X1=-8/2 - Square root of ((8/2)²+5) X1=-4 - Square root of 21 X1 is about -8.58 X2=-8/2 + Square root of ((8/2)²+5) X2=-4 + Square root of 21 X2 is about 0.58
square root of (x2 + 1) = no simplification (square root of x2) + 1 = x + 1
x2+3i=0 so x2=-3i x=square root of (-3i)=square root (-3)square root (i) =i(square root(3)([1/(square root (2)](1+i) and i(square root(3)([-1/(square root (2)](1+i) You can multiply through by i if you want, but I left it since it shows you where the answer came from. Note: The square root of i is 1/square root 2(1+i) and -1/square root of 2 (1+i) to see this, try and square them!
x2-b = 9 x2 = 9+b Square root both sides: x = the square root of (9+b)
Take the square root of both sides. x=the square root of 10. It is an irrational number. Approximately 3.15
x2+3=124 x2=121 x= square root(121) x=11
square root -5 minus 14 or - square root -5 minus 14