V = pi*r^2*h so r^2 = V/(pi*h) and so r = sqrt[V/(pi*h)].
(x - h)2 + (y - v)2 = r2
V=? h=15 units r=1/2diameter= 5 units V=pi(r^2)(h) V=pi(5^2)(15) V=1178.09724 units^3
H. V. R. Iyengar died in 1978.
Make r the subject of the formula pi*r2*h = V r = the square root of V/pi*h
V = pi*(r^2)*h is the formula for the volume of a cylinder. In order to solve for 'h' (or the height), do the following:V = pi*(r^2)*h --> divide both sides of the equation by pi*(r^2) to get rid of pi*(r^2) on the right side of the equation.V/(pi*(r^2)) = (pi*(r^2)*h)/(pi*(r^2)) --> cancel out the common term (pi*(r^2)) in the right side of the equation.You are left with the original equation in terms of 'h':h = V/(pi*(r^2))
V = pi*r^2*h V is volume pi is 3.142 r is the radius h is the height
The volume V of a cylinder with base of radius r is the product of the area B of a base and the height of the cylinder. V = Bh, or V = (pi)r^2h. So, h = V/B, or h = V/[(pi) r^2] V = 1590 cm^3, pi = 3.141, r = 7.5/2 = 3.75 cm, r^2 = 14.0625 cm^2 h = (1590 cm^3)/[(3.141)(14.0625 cm^2) h = 35.9957487 cm h is approximately 36 cm
If v = r * h then> r = v / h
V = (pi*h*r^2)/3 SA = pi*r*s + pi*r^2
Volume = (area of base) x (height) = pi*r2*hSurface area of the cylinder (think of a soup can): the top and bottom are the same; each is pi*r2, then the wall of the can unrolled is circumference of the circle times height: 2*pi*r*h.Surface area [A] = 2*pi*r2 + 2*pi*r*h; Use the constant volume to find h in terms of V and r: h = V/(pi*r2)A = 2*pi*r2 + 2*pi*r*V/(pi*r2) = 2*pi*r2 + 2*V*r-1To minimize area, take derivative with respect to r, set equal to zero & solve for r.dA/dr = 4*pi*r - 2*V*r-2 = 0 --> r3 = V/(2*pi); subst V = pi*r2*h --> r = h/2.So the Height is twice the radius (or the height is equal to diameter).
Circumference = C = 2*π*r where π = pi and r = radius 88=2πr 44=πr r = 14 inches Volume of a cylinder = V = π*r^2*h where h = height V= π*14^2*1 V= 3.142*196 V= 615.8 cubic inches
v = area of base * h = pi*r^2 * h so v = pi*15mm^2 * 300mm which can be done on a calculator.
Volume of a cylinder: V = pi * h * r^2 (where h=height and r=radius) So, plugging into the volume equation both possible scenarios and setting them equal to each other gives: pi * (r + x)^2 * h = pi * r^2 * (h + x) The pi's cancel and the squared terms give: (r^2 + 2rx + x^2) * h = (h * r^2) + (x * r^2) Simplifying and swapping terms: hx^2 + 2hrx - xr^2 = 0 hx^2 + x(2hr - r^2) = 0 hx^2 = -x(2hr - r^2) x = -(2hr - r^2)/h = (r^2 - 2hr)/h
Slice the bowl horizontally into circles, then integrate the area of the circles. The area of each circle is (pi * r^2). The height of each slice is dh. The 1st (bottom) circle is r=0. The r^2 of each circle-slice is (2*A*h-h^2), where A is the spherical radius, and h is the variable height of any given slice. At the top of the water level, (r^2=2*A*H-H^2). Integrate the area over the interval h=0->H as follows: V=pi * integral[(2*A*h - h^2) dh]; h=0->H to yield V=pi * (2*A*h^2 / 2 - h^3 / 3); h=0->H V=pi * (A*H^2 - H^3 / 3). As a check, plug the full diameter (2*A) in for H. If you did the integration correctly, you will get the full volume of the sphere, (4/3 * pi * A^3).
The volume V of a cylinder with base of radius r is the product of the area B of a base and the height h of the cylinder. V = Bh, or V = pi x r^2 x h By substituting the given values, r = 4 cm and h = 10 cm, we have: V = pi x 4^2 x 10 V = 160pi Thus, the volume of the cylinder is 160pi cm^3.
V=pi(r^2)h V=3.14(1^2)12 V=37.68 cubic inches