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Reduce its height

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Q: How do you keep the volume of a cylinder the same if the radius quadruples?
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How do you calculate the outside diameter of a steel coil based on the weight width and inside diameter?

You're essentially trying to calculate the diameter of a cylinder with a hole in the middle. There are two formulas for volume which you need. Volume= Pi * r2 * h (where Pi=3.142, r = radius of the coil, h = width of the coil) Volume= Weight/Density Since both these formula equal Volume: Weight/Density= Pi * r2 * h Since the weight you have is for a cylinder with a hole in it, you need to calculate the volume of the whole cylinder (without the hole) and subtract the volume of the hole. So for a steel coil Weight/Density = (Pi * rc2 * h)-(Pi * rh2 * h) where rc= the radius of the coil and rh = the radius of the hole (Radius=diameter/2) you're trying to calculate the radius of the coil, so rearrange the formula to get: ((Weight/Density)/Pi*h) + rh2 = rc2 The diameter of the coil = 2 *rc NOTE:- It's important to keep your units of measure consistent throughout the calculation. Density is generally represented by kilograms per cubic metre (kg/m3) - for us metric users ;-) Therefore keep your coil weight in kgs and your radius / width measures in metres.


How do you divide a circle in to 6th equal parts?

If you have a protractor: Draw a line from the center of the circle to the outside (radius), then measure 60 degrees and draw another line. If you have a compass: Draw a circle using the compass, then, using your compass, place the compass needle on the edge of the circle, draw another circle (KEEP THE RADIUS THE SAME). Your two circles should have two intersection points. Place the needle on one of the intersection points and repeat the process. I suggest you look at:


What is the area of 12 foot circle?

Assuming that the Diameter is 12 foot the radius would be 6 foot. So Area of a circle is found by Pi*r² So: 3.14 * 6² = 113.04ft² In conclusion: The area of a 12 foot circle would be 113.04ft² - To keep with significant figures the answer would be: 113ft²


Why are boxes square?

Because if they were such shapes as triangles, it would be hard to use up the extra volume area since most object shapes aren't shaped like wedges, you would have unused space. Keep in mind there are rectangular boxes too.


What is PI used for?

Pi is used to find a lot of things, volume, area, diameter, radius, but most commonly, circumference. To do that, you multiply the diameter of a circle by pi, (3.14159) then you have the circumference.it is used to calculate the area and volume of a circle or cylinderalso to find circumferenceEX:DIAMETER X PI = CIRCUMFERENCE+++True but I'd question the "most commonly" because Pi is also fundamental to a huge range of calculations involving motion or force in circular or circle-function paths, and to harmonic calculations (sound, vibration, electrical circuit laws, etc.).'Incidentally, there is a neat trick by pure co-incidence worth knowing if you often use a calculator or the calculator pad on a PC keyboard to find areas of circles from their diameters. The standard formula is Pi*R^2 where R is the circle's radius, but since 2R = Diameter the formula w.r.t Diameter is therefore (Pi*D^2)/4. Now, Pi/4 = 0.7854 to enough decimal places for most everyday calculations, so then the formula simplifies to 0.7854*D^2. Look at your keypad and you see those 4 digits sit in a tidy square in the top left, nice and easy to find if you need to keep entering them!

Related questions

How many times greater is the volume of a cylinder with a radius of 5 than a radius of 2.5?

Volume of a cylinder is given by the formula: V = πr2hIt is important to keep in mind that:If r is doubled then volume becomes four times....(1)Volume of the cylinder with radius of 2.5 units is equal to π(2.5)2h and volume of the cylinder with radius of 5 units is equal to 4π(2.5)2h. (By using the fact (1))So, it is clear that volume of the cylinder with greater radius is 4 times the volume of the cylinder with smaller radius.


How do you calculate the outside diameter of a steel coil based on the weight width and inside diameter?

You're essentially trying to calculate the diameter of a cylinder with a hole in the middle. There are two formulas for volume which you need. Volume= Pi * r2 * h (where Pi=3.142, r = radius of the coil, h = width of the coil) Volume= Weight/Density Since both these formula equal Volume: Weight/Density= Pi * r2 * h Since the weight you have is for a cylinder with a hole in it, you need to calculate the volume of the whole cylinder (without the hole) and subtract the volume of the hole. So for a steel coil Weight/Density = (Pi * rc2 * h)-(Pi * rh2 * h) where rc= the radius of the coil and rh = the radius of the hole (Radius=diameter/2) you're trying to calculate the radius of the coil, so rearrange the formula to get: ((Weight/Density)/Pi*h) + rh2 = rc2 The diameter of the coil = 2 *rc NOTE:- It's important to keep your units of measure consistent throughout the calculation. Density is generally represented by kilograms per cubic metre (kg/m3) - for us metric users ;-) Therefore keep your coil weight in kgs and your radius / width measures in metres.


How would you changed the height of a cone so that its volume would remain the same when its radius was tripled?

V = (pi) R^2 H/3 if radius triples then volume goes as radius squared = 9 times more, so you would need to reduce height by 9 to keep same volume


The coffee can is three fourths full The radius is 3in and the height is 8in tall How much coffee is in the can?

Volume of a cylinder = pi*r2*h You have r and h already. You should know what pi equals. Solve the equation and multiply your answer by .75, since the can is only 3/4 full. Remember to keep track of your units - you will end up with units of volume. You do the rest.


How many cubic inches in a 6 inch diameter cylinder 1 inch tall?

Keep it simple. Break it down. (Area of piston face) times the (stroke/height/tall), equals (Volume/Cubic Inches). So..., "A=Pi R2" translated is A (Area)= 3.14159 (Pi) X R (Radius) squared (R2), therefore done as an Algebra formula, work it from the inside out starting with the Radius first! 1/2 of the diameter of 1.125 = .5625 is the Radius. .5625 X .5625 = .31641 is the Radius squared. .31641 (Radius squared) X 3.14159(Pi) = .9940 (Area) .9940 (Area) times the (stroke/tall) being 2.250 = 2.2365 cubic inches/volume.


What lab equipment is most useful in finding the denisty of an object?

A scale, a beaker and a graduated cylinder. You use the scale to determine the mass of the object. If it is a solid, you can just place it on the scale. If it is a liquid you have to keep it in a graduated cylinder or beaker and weigh it. But remember to subtract the weight of the beaker/graduated cylinder. Then you have to find the volume. For a liquid, this is very easy. Just put it into a graduated cylinder and read the ml on the side. If it's a solid, then there are two ways to do it. If it is a very even shape, such as a cube or a cylinder etc, you can take precise measurements and use the volume equations available for the certain shape. Another way is to do water displacement. Put water into the beaker and record the volume. Then put the solid in the water (make sure the solid doesn't dissolve in water first). Record the volume and subtract the original volume. The density is just mass divided by volume.


What is the function of residual volume?

The function of residual volume is to keep enough pressure in the lungs to keep them from collapsing.


What is the job of wheel cylinder stops?

Wheel cylinder stops would keep the wheel cylinder from coming apart.


What is Procedure that helps determine the volume of an irregularly shaped object while using a graduated cylinder?

Yes you can. You put liquid (usually water) in the graduated cylinder. Then record how much liquid you put in it. Next, put the object in the graduated cylinder. Look at where the water level is now. Take that number and subtract the amount of water you put in and that should give you the approximate volume of the object.


Where is the firing safety on Colt Cobra?

there are no safeties on revolvers. keep cylinder under hammer empty or keep cylinder empty. then gun is safe....................


Do solids keep their volumes?

Yes, solids keep their volume.


Do gases keep the same volume?

Usually not. They can easily expand into a larger volume, or be compressed into a smaller volume.