V = pi r^2*H
&
V = pi (4r)^2*h
Equate
pi r^(2)H= pi (4r)^2 h
pi cancel down
r^(2)H = (4r)^2h
r^(2)*H = 16r^(2)*h
'r^(2) cancels down
H= 16h
h = H/16
This means is you increase the radius by '4 times' , then you reduce the height(H) by '16 times' in order to maintain the same volume.
You're essentially trying to calculate the diameter of a cylinder with a hole in the middle. There are two formulas for volume which you need. Volume= Pi * r2 * h (where Pi=3.142, r = radius of the coil, h = width of the coil) Volume= Weight/Density Since both these formula equal Volume: Weight/Density= Pi * r2 * h Since the weight you have is for a cylinder with a hole in it, you need to calculate the volume of the whole cylinder (without the hole) and subtract the volume of the hole. So for a steel coil Weight/Density = (Pi * rc2 * h)-(Pi * rh2 * h) where rc= the radius of the coil and rh = the radius of the hole (Radius=diameter/2) you're trying to calculate the radius of the coil, so rearrange the formula to get: ((Weight/Density)/Pi*h) + rh2 = rc2 The diameter of the coil = 2 *rc NOTE:- It's important to keep your units of measure consistent throughout the calculation. Density is generally represented by kilograms per cubic metre (kg/m3) - for us metric users ;-) Therefore keep your coil weight in kgs and your radius / width measures in metres.
Volume of the sphere: 4/3*pi*2^3 = 33.5 cubic meters to one decimal place
If you have a protractor: Draw a line from the center of the circle to the outside (radius), then measure 60 degrees and draw another line. If you have a compass: Draw a circle using the compass, then, using your compass, place the compass needle on the edge of the circle, draw another circle (KEEP THE RADIUS THE SAME). Your two circles should have two intersection points. Place the needle on one of the intersection points and repeat the process. I suggest you look at:
Assuming that the Diameter is 12 foot the radius would be 6 foot. So Area of a circle is found by Pi*r² So: 3.14 * 6² = 113.04ft² In conclusion: The area of a 12 foot circle would be 113.04ft² - To keep with significant figures the answer would be: 113ft²
Because if they were such shapes as triangles, it would be hard to use up the extra volume area since most object shapes aren't shaped like wedges, you would have unused space. Keep in mind there are rectangular boxes too.
Volume of a cylinder is given by the formula: V = πr2hIt is important to keep in mind that:If r is doubled then volume becomes four times....(1)Volume of the cylinder with radius of 2.5 units is equal to π(2.5)2h and volume of the cylinder with radius of 5 units is equal to 4π(2.5)2h. (By using the fact (1))So, it is clear that volume of the cylinder with greater radius is 4 times the volume of the cylinder with smaller radius.
You're essentially trying to calculate the diameter of a cylinder with a hole in the middle. There are two formulas for volume which you need. Volume= Pi * r2 * h (where Pi=3.142, r = radius of the coil, h = width of the coil) Volume= Weight/Density Since both these formula equal Volume: Weight/Density= Pi * r2 * h Since the weight you have is for a cylinder with a hole in it, you need to calculate the volume of the whole cylinder (without the hole) and subtract the volume of the hole. So for a steel coil Weight/Density = (Pi * rc2 * h)-(Pi * rh2 * h) where rc= the radius of the coil and rh = the radius of the hole (Radius=diameter/2) you're trying to calculate the radius of the coil, so rearrange the formula to get: ((Weight/Density)/Pi*h) + rh2 = rc2 The diameter of the coil = 2 *rc NOTE:- It's important to keep your units of measure consistent throughout the calculation. Density is generally represented by kilograms per cubic metre (kg/m3) - for us metric users ;-) Therefore keep your coil weight in kgs and your radius / width measures in metres.
V = (pi) R^2 H/3 if radius triples then volume goes as radius squared = 9 times more, so you would need to reduce height by 9 to keep same volume
The volume of a cylinder is calculated using the formula V = πr^2h, where r is the radius and h is the height. Given a 6-inch diameter (radius of 3 inches) and a height of 1 inch, the volume would be V = π(3)^2(1) = 9π cubic inches, or approximately 28.27 cubic inches.
To find the diameter of a cylinder, you need the mass, density, and height of the cylinder. First, calculate the volume of the cylinder using the formula: volume = mass / density. Then divide the volume by the height to get the cross-sectional area of the cylinder. Finally, use the formula for the area of a circle (πr^2) to find the radius, and double it to get the diameter.
Volume of a cylinder = pi*r2*h You have r and h already. You should know what pi equals. Solve the equation and multiply your answer by .75, since the can is only 3/4 full. Remember to keep track of your units - you will end up with units of volume. You do the rest.
Ah, what a lovely question! To find the circumference of a cylinder, you'll want to use the formula 2πr, where r is the radius of the cylinder. Since the diameter is 16 inches, the radius would be half of that, which is 8 inches. So, the circumference would be 2 x π x 8, which is approximately 50.24 inches. Keep painting with those happy little numbers!
A scale, a beaker and a graduated cylinder. You use the scale to determine the mass of the object. If it is a solid, you can just place it on the scale. If it is a liquid you have to keep it in a graduated cylinder or beaker and weigh it. But remember to subtract the weight of the beaker/graduated cylinder. Then you have to find the volume. For a liquid, this is very easy. Just put it into a graduated cylinder and read the ml on the side. If it's a solid, then there are two ways to do it. If it is a very even shape, such as a cube or a cylinder etc, you can take precise measurements and use the volume equations available for the certain shape. Another way is to do water displacement. Put water into the beaker and record the volume. Then put the solid in the water (make sure the solid doesn't dissolve in water first). Record the volume and subtract the original volume. The density is just mass divided by volume.
Volume of the sphere: 4/3*pi*2^3 = 33.5 cubic meters to one decimal place
Wheel cylinder stops would keep the wheel cylinder from coming apart.
The function of residual volume is to keep enough pressure in the lungs to keep them from collapsing.
there are no safeties on revolvers. keep cylinder under hammer empty or keep cylinder empty. then gun is safe....................