x2 + 5x + 6 = (x + 2)(x + 3)
x2 + 5x + 3 = 9 x2 + 5x - 6 = 0 (x + 6)(x - 1) = 0 x = -6 or x = 1
x2+5x-6 = (x+6)(x-1) when factored
x2+5x+6 = (x+2)(x+3) when factored because 2 and 3 are factors of 6
x2 + 5x - 6 = x2 + 6x - x - 6 = x(x + 6) - 1(x + 6) = (x - 1)(x + 6)
x2 + 5x + 6 = (x + 2)(x + 3)
x2 - 5x + 6 = (x - 2)(x - 3)
x2 + 5x + 3 = 9 x2 + 5x - 6 = 0 (x + 6)(x - 1) = 0 x = -6 or x = 1
x2+5x+6 = (x+2)(x+3)
x2+5x-6 = (x+6)(x-1) when factored
x2+5x+6 = (x+2)(x+3) when factored because 2 and 3 are factors of 6
x2 + 5x - 6 = x2 + 6x - x - 6 = x(x + 6) - 1(x + 6) = (x - 1)(x + 6)
x(x2+5x+6)
(x-6)(x+1)
x - 3
x2 + 5x - 120 can not be factored.
If you mean: x2+5x+6 = 0 then the solutions are x = -3 and x = -2