2x2+5x-3 = 0 (2x-1)(x+3) = 0 x = 1/2 or x -3
2x+3x-2=0=5x=0+2=5x=2=5x_5=2_5=x=0.4
-4 5x + 2 = -18 0x + -2 = -2 ---------------- 5x + 0 = -20 5x / 5 = -20/5 x = -4
0. 6x + 3 = 5x + 141. 6x = 5x + 11 [subtracting 3]2. x = 11 [subtracting 5x]
17x2-11x+2 = 2x2 Subtract 2x2 from both sides: 15x2-11x+2 = 0 Factorise: (3x-1)(5x-2) = 0 Solution: x =1/3 or x = 2/5
I could be missing something here, but I'm pretty sure the two 5x's cancel out and you would get 2=0, which is not true. so the answer would be no solution. Hope that helps!
2x2+5x-3 = 0 (2x-1)(x+3) = 0 x = 1/2 or x -3
x2 - 5x + 6 = 0(x - 2) (x - 3) = 0x - 2 = 0 5 × 69 or x - 3 = 0x = 2 or x = 3
2x+3x-2=0=5x=0+2=5x=2=5x_5=2_5=x=0.4
-4 5x + 2 = -18 0x + -2 = -2 ---------------- 5x + 0 = -20 5x / 5 = -20/5 x = -4
x2 + 5x + 6 = 0 (x + 3)(x + 2) = 0 So x + 3 = 0 or x + 2 = 0 So x = -3 or x = -2
0. 6x + 3 = 5x + 141. 6x = 5x + 11 [subtracting 3]2. x = 11 [subtracting 5x]
17x2-11x+2 = 2x2 Subtract 2x2 from both sides: 15x2-11x+2 = 0 Factorise: (3x-1)(5x-2) = 0 Solution: x =1/3 or x = 2/5
In the equation 43X +2=5X, X=-1/19.
5times2+x-2=0 8+x=0 x=(-0) OR 5times(2+x)-2=0 8+5x=0 5x=(-8) x=(-8/5)
If you mean 5x^2 -7x +2 = 0 then it is a quadratic equation with solutions of x = 2/5 or x = 1
Put in point slope/function form. 5X + 2Y + 3 = 0 5X + 2Y = - 3 2Y = - 5X - 3 Y = - 5/2X - 3/2 slope = - 5/2 ---------------- Y intercept = - 3/2 -------------------------