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x2+2x+2=0
Using the quadratic formula
x= (-2+- sq.root (22-4.1.2))/2
x= (-2+- sq.root(4-8))/2
x= (-2+- sq.root -4)/2
x= (-2+- 2i)/2
x= -2+2i and -2-2i which then simplifies to -1+i and -1-i.
Hope this wasn't too confusing.
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X2 plus 2x plus -6 equals 0?
x2 + 2x -6 = 0 x2 + 2x + 1 = 7 (x + 1)2 = 7 x = -1 ± √7
2x equals x2 plus 4x-3?
2x = x2 + 4x - 3 x2 + 2x - 3 = 0 (x - 1)(x - 2) = 0
X squared plus 2x - 3 equals 0?
If: x2+2x-3 = 0 Then: x = 1 or x = -3
What is the solution to x2 plus 10x plus 1 equals -12 plus 2x?
x2+10x+1 = -12+2x x2+10x-2x+1+12 = 0 x2+8x+13 = 0 Solving by using the quadratic equation formula: x = - 4 - or + the square root of 3
X2 plus 8x equals -3x2 plus 5?
x2+8x = -3x2+5 4x2+8x-5 = 0 (2x+5)(2x-1) = 0 x = -5/2 or x = 1/2
X2 plus 2x plus -6 equals 0?
x2 + 2x -6 = 0 x2 + 2x + 1 = 7 (x + 1)2 = 7 x = -1 ± √7
2x equals x2 plus 4x-3?
2x = x2 + 4x - 3 x2 + 2x - 3 = 0 (x - 1)(x - 2) = 0
X squared plus 2x - 3 equals 0?
If: x2+2x-3 = 0 Then: x = 1 or x = -3
What is the solution to x2 plus 10x plus 1 equals -12 plus 2x?
x2+10x+1 = -12+2x x2+10x-2x+1+12 = 0 x2+8x+13 = 0 Solving by using the quadratic equation formula: x = - 4 - or + the square root of 3
Y equals x2 plus 2x plus 1?
y = x2 + 2x + 1zeros are:0 = x2 + 2x + 10 = (x + 1)(x + 1)0 = (x + 1)2x = -1So that the graph of the function y = x + 2x + 1 touches the x-axis at x = -1.
Solve x2 plus 2x - 13 equals 2?
x2 + 2x - 13 = 2 x2 + 2x - 15 = 0 (x + 5)(x - 3) = 0 x + 5 = 0 and x - 3 = 0 so x = -5 and x = 3
X2 plus 8x equals -3x2 plus 5?
x2+8x = -3x2+5 4x2+8x-5 = 0 (2x+5)(2x-1) = 0 x = -5/2 or x = 1/2
Put the equation in the form ax2 plus bx plus c equals 0 x2-3 equals 3x2 plus 8x?
2x^2 + 8x + 3 = 0
What use the discriminant to determine the nature of the roots of x2 plus 2x plus 5 equals 0?
No real roots
X squared plus 2x - 15 equals 0?
x2 + 2x - 15 = 0(x + 5) (x - 3) = 0x = -5x = +3
What is the answer for this equation x squared plus 2x-38 equals 0?
x2 + 2x - 38 = 0 ∴ x2 + 2x + 1 = 39 ∴ (x + 1)2 = 39 ∴ x + 1 = ±√39 ∴ x = -1 ±√39
What are the points of intersection of y equals x squared plus 2x plus 2 with y equals x cubed plus 2?
x2-x3+2x = 0 x(-x2+x+2) = 0 x(-x+2)(x+1) = 0 Points of intersection are: (0, 2), (2,10) and (-1, 1)
